Solve Problem 2IR Spectrum(liquid film)335440003000200016001200800V (cm')100Mass Spectrum4580FNo significant UVabsorption above 220 nmM*' - 60 (< 1%)59C3H3O4080120160200240280m/e13C NMR Spectrum(50.0 MHz, CDCI, solution)proton coupledsolventproton decoupled16012080408 (ppm)2001H NMR Spectrum(200 MHz. CDCI, solution)expansionsTMSppmexchangeswith D201.51.04.54.0ppm6438.8 (ppm)10% of base peak

The chemical formula of the given organic compound is C3H8O Double bond equivalent, DBE =…

Problem 2 IR Spectrum (liquid film) 3354 4000 3000 2000 1600 1200 800 v (cm') 100 Mass Spectrum 45 80 60 No significant UV absorption above 220 nm 40 M*' - 60 (< 1%) 20 59 C3HBO 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) ll proton coupled solvent proton decoupled 160 120 80 40 8 (ppm) 200 H NMR Spectrum (200 MHz, CDCI, solution) expansions TMS exchanges with D20 1.0 ppm 1.5 4.5 4.0 ppm 6. 5. 4 3 2 1. 10 6. 8. 8 (ppm) of base peak

Problem 2 IR Spectrum (liquid film) 3354 4000 3000 2000 1600 1200 800 v (cm') 100 Mass Spectrum 45 80 60 No significant UV absorption above 220 nm 40 M*' - 60 (< 1%) 20 59 C3HBO 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) ll proton coupled solvent proton decoupled 160 120 80 40 8 (ppm) 200 H NMR Spectrum (200 MHz, CDCI, solution) expansions TMS exchanges with D20 1.0 ppm 1.5 4.5 4.0 ppm 6. 5. 4 3 2 1. 10 6. 8. 8 (ppm) of base peak

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter4: Least-squares And Calibration Methods

Section: Chapter Questions

Problem 11P

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