Problem 2.445 of 8Constants Periodic TableAn unmarked police car traveling a constant 95.0 km/h is passed byspeeder traveling 140 km/haPart APrecisely 3.00 s after the speeder passes, the police officer steps on the accelerator, if the police car's acceleration is 1.90 m/s2 , how much time passes before the policecar overtakes the speeder after the speeder passes (assumed moving at constant speed)?1 ΑΣφ?15.1t =Previous AnswersRequest AnswerSubmitX Incorrect; Try Again; 8 attempts remaining

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Asked Sep 4, 2019
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I've attached a screenshot of the question i'm trying to solve and I have pictures of my work here https://imgur.com/a/bQ5IaC1 . My work for this problem is under the 2.44 title, any variable with an "s" in the subscript applies to the speeder, and any variable with a "c" in the subscript applies to the police car.

Problem 2.44
5 of 8
Constants Periodic Table
An unmarked police car traveling a constant 95.0 km/h is passed by
speeder traveling 140 km/h
a
Part A
Precisely 3.00 s after the speeder passes, the police officer steps on the accelerator, if the police car's acceleration is 1.90 m/s2 , how much time passes before the police
car overtakes the speeder after the speeder passes (assumed moving at constant speed)?
1 ΑΣφ
?
15.1
t =
Previous Answers
Request Answer
Submit
X Incorrect; Try Again; 8 attempts remaining
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Problem 2.44 5 of 8 Constants Periodic Table An unmarked police car traveling a constant 95.0 km/h is passed by speeder traveling 140 km/h a Part A Precisely 3.00 s after the speeder passes, the police officer steps on the accelerator, if the police car's acceleration is 1.90 m/s2 , how much time passes before the police car overtakes the speeder after the speeder passes (assumed moving at constant speed)? 1 ΑΣφ ? 15.1 t = Previous Answers Request Answer Submit X Incorrect; Try Again; 8 attempts remaining

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Expert Answer

Step 1

The speed of the police car is 95 km/h, and the speed of the traveler is 140 km/h.

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The position of the traveler is 0+140km/hx 0.278m/s 1km/h -39m/s xt position of the police car )(0-39j 0.278m/s(3s) xp X (3s)+ vop(t-3s)+- 95km/h x0.278m/s 1km/h (1.90m/s"(t-3s) (t-3s) 5 km/ h x =0+ X 1km/h = 0.952 20.7t +8.55

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Step 2

When the position of officer and spe...

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= 39m/s xt 0.952 +20.7t +8.55 0.952-18.3t8.55 = 0 418.8s, t 0.479s

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