Question

Part d please

Step 1

Left hand limit of x=0 is=0+1=1

Right hand limit of x=0 is= -infinity

So, at x=0 it is discontinuous

Step 2

Left hand limit of x=1 is =0

Right hand limit of x=1 is = 1

So h(x) is discontinuous at x=1

Answer(a): h(x) is discontinuous at x=0 and x=1

Step 3

Both at x=0 and x=1 it is left continuous , because equality holds at left...

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