Problem 4.Calcium chloride is a salt used in a number of food and medicinal applications and in fluid forrefrigeration systems. Its most distinctive property is its affinity for water: in its anhydrous formit efficiently absorbs water vapour from gases, and from aqueous liquid solutions it can form(under different conditions) calcium chloride hydrate (CaCl2-H20), dihydrate (CaCl2 2H2O),tetrahydrate (CaCl2-4H2O) and hexahydrate (CaCl2-6H2O).You have been given the task of determining the standard heat of of the reaction in which calciumchloride hexahydrate is formed from anhydrous calcium chloride:AH (k) ?CaCl2(s)6H20 CaCl2-6H20 (s)By definition, the desired quantity is the heat of hydration of calcium chloride hexahydrate. Youcannot carry out the hydration reaction directly, so you resort to an indirect moethod. You firstdissolve 1 mol of anhydrous (no water) CaCl2 in 10 mol of water in a calorimeter and determinethat 64.85 kJ of heat must be transferred away from the calorimeter to keep the solutiontemperature at 25°C. You next dissolve 1 mol of the hexahydrate salt in 4 mol of water and findthat 32.41 kJ of heat must be transferred to the calorimeter to keep the temperature at 25°CUse these results to calculate the desired heat of reaction (Hint: remember Hess' Law)

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Asked Oct 22, 2019
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Problem 4.
Calcium chloride is a salt used in a number of food and medicinal applications and in fluid for
refrigeration systems. Its most distinctive property is its affinity for water: in its anhydrous form
it efficiently absorbs water vapour from gases, and from aqueous liquid solutions it can form
(under different conditions) calcium chloride hydrate (CaCl2-H20), dihydrate (CaCl2 2H2O),
tetrahydrate (CaCl2-4H2O) and hexahydrate (CaCl2-6H2O).
You have been given the task of determining the standard heat of of the reaction in which calcium
chloride hexahydrate is formed from anhydrous calcium chloride:
AH (k) ?
CaCl2(s)6H20 CaCl2-6H20 (s)
By definition, the desired quantity is the heat of hydration of calcium chloride hexahydrate. You
cannot carry out the hydration reaction directly, so you resort to an indirect moethod. You first
dissolve 1 mol of anhydrous (no water) CaCl2 in 10 mol of water in a calorimeter and determine
that 64.85 kJ of heat must be transferred away from the calorimeter to keep the solution
temperature at 25°C. You next dissolve 1 mol of the hexahydrate salt in 4 mol of water and find
that 32.41 kJ of heat must be transferred to the calorimeter to keep the temperature at 25°C
Use these results to calculate the desired heat of reaction (Hint: remember Hess' Law)
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Problem 4. Calcium chloride is a salt used in a number of food and medicinal applications and in fluid for refrigeration systems. Its most distinctive property is its affinity for water: in its anhydrous form it efficiently absorbs water vapour from gases, and from aqueous liquid solutions it can form (under different conditions) calcium chloride hydrate (CaCl2-H20), dihydrate (CaCl2 2H2O), tetrahydrate (CaCl2-4H2O) and hexahydrate (CaCl2-6H2O). You have been given the task of determining the standard heat of of the reaction in which calcium chloride hexahydrate is formed from anhydrous calcium chloride: AH (k) ? CaCl2(s)6H20 CaCl2-6H20 (s) By definition, the desired quantity is the heat of hydration of calcium chloride hexahydrate. You cannot carry out the hydration reaction directly, so you resort to an indirect moethod. You first dissolve 1 mol of anhydrous (no water) CaCl2 in 10 mol of water in a calorimeter and determine that 64.85 kJ of heat must be transferred away from the calorimeter to keep the solution temperature at 25°C. You next dissolve 1 mol of the hexahydrate salt in 4 mol of water and find that 32.41 kJ of heat must be transferred to the calorimeter to keep the temperature at 25°C Use these results to calculate the desired heat of reaction (Hint: remember Hess' Law)

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Expert Answer

Step 1

Given

The desired reaction according to which the product formation takes place

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СаCl, 6H,0 СаСl, бH,0 +

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Step 2

The first reaction happens with one mole of calcium chloride in 10 mol of water

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СаCly 10н,0- СаCly 10H,0

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Step 3

The second reaction takes place with one mole...

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CaCl2 6H20 4H20 CaCl2 10H20

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