Problem 5A vertical, rectangular loop fall out of a region where the magnetic field is uniform, into a regionwith no field. The loop has resistance R, mass m, horizontal sides of width w, and vertical sidesheight H. It is released from rest (vo = 0.) The magnetic field in the upper region is horizontal andhas magnitude B(a) Find the current I in the loop when it attains a speed v (in terms of the given parameters.)(b) Find the net force on the loop when it has speed v, assuming the bottom of the loop is in thelower, B 0, region but the top is still in the upper, B /0 region, again in terms of the givenparameters(c) The loop will eventually reach a terminal velocity, a constant speed. Explain why this is true,and find an expression for that terminal velocity(d) How should the terminal velocity depend on the mass of the loop, the resistance of the loop,and the magnetic field strength?(e) What is the terminal velocity of a loop of copper wire, 0.50 m wide, 0.0010 kg mass, resistanceof 0.0032, falling out of a 0.00005 T field (the approximate field of the earth)? You might noticethat you get a really large terminal velocity! We should have expected that; why?

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Could you answer only D and E for me, thank you.

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Step 1

Given:

Resistance of the loop = R

Mass of the loop = m

Horizontal length(Width) of the loop = w

Vertical length(length) of the loop = H

Initial velocity of the loop = 0 m/s

Magnetic field = B

Step 2

Calculating the terminal velocity of the loop:

Terminal velocity is the velocity when force of weight of loop becomes equal to the force on the loop by magnetic field due to induced current in the loop.So, when the net force on the loop becomes zero, the loop falls with a constant velocity, known as terminal velocity.

Step 3

Determining how the terminal velocity depends on mas...

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