Database SchemaThe schema for the Ch07_FACT database is shown below and should be used to answer thenext several problems. Click this image to view it in its own tab.FIGURE P7.56 THE CH07_FACT ERDCHECKOUTPATRONPKCheck NumPK Pat IDFK1 Book_NumFK2 Pat_IDCheck_Out_DateCheck_Due_DateCheck_In_Date>0-----H-Pat_FNamePat LNamePat_TypeBOOKAUTHORPKBook_NumPK Au IDBook_TitleBook_YearBook_CostBook_SubjectFK1 Pat_IDAu_FNameAu_LNameAu_BirthYearWRITESPK,FK1 Book NumPK,FK2 Au IDThe CIS Department at Tiny College maintains the Free Access to Current Technology (FACT)library of e-books. FACT is a collection of current technology e-books for use by faculty andstudents. Agreements with the publishers allow patrons to electronically check out a book, Problem 81Write a query to display the highest book cost in the system (Figure P7.81).Most Expensive129.95Figure 7.81Task

Consider the following query to display the most expensive book in the FACT system: Query: select…

Answered: Problem 81 Write a query to display the…

Problem 81 Write a query to display the highest book cost in the system (Figure P7.81). Most Expensive 12995 Figure 7.81

A Guide to SQL

9th Edition

ISBN:9781111527273

Author:Philip J. Pratt

Publisher:Philip J. Pratt

Chapter2: Database Design Fundamentals

Section: Chapter Questions

Problem 11RQ

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The following tables provide a very small portion of the data that will be kept in the database. These data need to be inserted into the database for testing purposes. Write the INSERT commands necessary to place the following data in the tables that were created in Problem 65. RENTAL RENT_NUM RENT_DATE MEM_NUM 1001 01-MAR-13 103 1002 01-MAR-13 105 1003 02-MAR-13 102 1004 02-MAR-13 110 1005 02-MAR-13 111 1006 02-MAR-13 107 1007 02-MAR-13 104 1008 03-MAR-13 105 1009 03-MAR-13 111 VIDEO VID_NUM VID_INDATE MOVIE_NUM 54321 18-JUN-12 1234 54324 18-JUN-12 1234 54325 18-JUN-12 1234 34341 22-JAN-11 1235 34342 22-JAN-11 1235 34366 02-MAR-13 1236 34367 02-MAR-13 1236 34368 02-MAR-13 1236 34369 02-MAR-13 1236 44392 21-OCT-12 1237 44397 21-OCT-12 1237 59237 14-FEB-13 1237 61388 25-JAN-11 1239 61353 28-JAN-10 1245 61354 28-JAN-10 1245 61367 30-JUL-12 1246 61369 30-JUL-12 1246
Which of the following data dictionary objects should be used to view information about the constraints in a database? USER_TABLES USER_RULES USER_COLUMNS USER_CONSTRAINTS None of the above objects should be used.
3.9 LAB - Select lesson schedule with inner join The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule. Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDs.
Write Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule. Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDs.
Part A: MySQL Query/Exec Create StudentsDB database in MySQL server with the following table: Table: Students uid int, Primary Key, Auto Increment studentID varchar(8), Unique name varchar(50) major varchar(50) passedCredits int CGPA float Implement the following PHP scripts as required below: php: the script should display student’s info (StudentID, name, major, credits passed and CGPA) in HTML table with appropriate title for each column. Student cells/rows should be highlighted as follows: Condition Highlight Color Student At Risk: CGPA < 2.0 Red for CGPA Cell Expected to graduate: Passed Credits >=115 Yellow for Passed Credits Cell Outstanding Student: CGPA = 3.5 or above Green for the entire Student Row php: This script should display all students’ names and major. Each student will be identified by a checkbox (define the checkbox name as a numeric array holding the uid). The…
We need to create a database for the Circulation Department of a public library. The database will store information about the patrons, books, and circulation. It contains the following: 4 tables for the database: PATRON, BOOK_COPY, BOOK, and CHECKOUT. (Since a book may have multiple copies that may be purchased by the library at different time, it is better to have a BOOK_COPY table to avoid unnecessary data redundancy.) The data in the tables are as follows: PATRON table records a patron’s ID, name, address, phone number, and email address. BOOK table contains information such as author, title, publication date, subject, language, and a unique identifier (It can be the ISBN of the book) for each book. BOOK_COPY table records a unique identifier for each copy of a book, the date of purchase, and the identifier of the book from the BOOK table. CHECKOUT table records the date of check-out, patron’s ID, the…
We need to create a database for the Circulation Department of a public library. The database will store information about the patrons, books, and circulation. It contains the following: 4 tables for the database: PATRON, BOOK_COPY, BOOK, and CHECKOUT. (Since a book may have multiple copies that may be purchased by the library at different time, it is better to have a BOOK_COPY table to avoid unnecessary data redundancy.) The data in the tables are as follows: PATRON table records a patron’s ID, name, address, phone number, and email address. BOOK table contains information such as author, title, publication date, subject, language, and a unique identifier (It can be the ISBN of the book) for each book. BOOK_COPY table records a unique identifier for each copy of a book, the date of purchase, and the identifier of the book from the BOOK table. CHECKOUT table records the date of check-out, patron’s ID, the…
We need to create a database for the Circulation Department of a public library. The database will store information about the patrons, books, and circulation. It contains the following: 4 tables for the database: PATRON, BOOK_COPY, BOOK, and CHECKOUT. (Since a book may have multiple copies that may be purchased by the library at different time, it is better to have a BOOK_COPY table to avoid unnecessary data redundancy.) The data in the tables are as follows: PATRON table records a patron’s ID, name, address, phone number, and email address. BOOK table contains information such as author, title, publication date, subject, language, and a unique identifier (It can be the ISBN of the book) for each book. BOOK_COPY table records a unique identifier for each copy of a book, the date of purchase, and the identifier of the book from the BOOK table. CHECKOUT table records the date of check-out, patron’s ID, the…
Computer engineering lab ApexSOQL - salesforce object query languageWhy i am getting this error in the below queryHere is the query -List<Prod2> productList = [Select Id, Name, Parent_Product__c, IsActive, Description, Account__c, (Select Id, Product2Id, Quantity From OrderItem) From Prod2 Where Account__c = 'XYZ'];ERROR at Row:3:Column:70I am not able to understand the relation between the OrderItem Object from the above query.Please resolve the error and provided me solution so i can solve it.Solve in Apex
I can't get the coding right on this one, I think I'm missing something here. Can anyone help please? 1.11 LAB - Query execution plans (Sakila) This lab illustrates how minor changes in a query may have a significant impact on the execution plan. MySQL Workbench exercise Refer to the film, actor, and film_actor tables of the Sakila database. This exercise is based on the initial Sakila installation. If you have altered these tables or their data, your results may be different. Do the following in MySQL Workbench: Enter the following statements: USE sakila; SELECT last_name, first_name, ROUND(AVG(length), 0) AS average FROM actor INNER JOIN film_actor ON film_actor.actor_id = actor.actor_id INNER JOIN film ON film_actor.film_id = film.film_id WHERE title = "ALONE TRIP" GROUP BY last_name, first_name ORDER BY average; Highlight the SELECT query. In the main menu, select Query > Explain Current Statement. In the Display Info box, highlighted in red below, select Data Read per Join.…
The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results.
Write Mysql code for: The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.

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