ProblemA sample of a dry coarse grained material of 500 grams was shaken through a nest of sieves and the following resultsare obtained:Sieve No.410204060100200PanOpening (mm)% Passing4.752.000.850.4250.250.150.075--946030105317. Determine the uniformity coefficient.18. Determine the coefficient of curvature.19. Given that the soil is non-plastic, classify the soil by using the Unified Soil Classification System.

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Problem A sample of a dry coarse grained material of 500 grams was shaken through a nest of sieves and the following results are obtained: Sieve No. Opening (mm) % Passing 10 20 40 60 0.25 4 100 200 Pan 4.75 2.00 0.85 0.15 0.075 0.425 10 94 60 30 17. Determine the uniformity coefficient. 18. Determine the coefficient of curvature. 19. Given that the soil is non-plastic, classify the soil by using the Unified Soil Classification System.

Problem A sample of a dry coarse grained material of 500 grams was shaken through a nest of sieves and the following results are obtained: Sieve No. Opening (mm) % Passing 10 20 40 60 0.25 4 100 200 Pan 4.75 2.00 0.85 0.15 0.075 0.425 10 94 60 30 17. Determine the uniformity coefficient. 18. Determine the coefficient of curvature. 19. Given that the soil is non-plastic, classify the soil by using the Unified Soil Classification System.

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter2: Geotechnical Properties Of Soil

Section: Chapter Questions

Problem 2.27P

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