Propane, C3H8 (approximate molar mass = 44 g/mol) is used in gas barbeques and burns according to the thermochemical equation: C3H8(g) + 5 O2(g)3 CO2(g) + 4 H2O(g) AH =-2046 kJ. If it takes 1.8 x 10 kJ to fully cook a rack of lamb on a gas barbeque, how many grams of propane will be required, assuming all the heat from the combustion reaction is absorbed by the lamb? Give your answer to 2 significant figures, but not in scientific notation.

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Propane, C3H8 (approximate molar mass = 44 g/mol) is used in gas barbeques and burns according to the thermochemical equation: C3H8(g) + 5 O2(g) → 3 CO2(g) + 4
H20(g) AH =-2046 kJ. If it takes 1.8 x 10° kJ to fully cook a rack of lamb on a gas barbeque, how many grams of propane will be required, assuming all the heat from the
%3D
combustion reaction is absorbed by the lamb? Give your answer to 2 significant figures, but not in scientific notation.
Transcribed Image Text:Propane, C3H8 (approximate molar mass = 44 g/mol) is used in gas barbeques and burns according to the thermochemical equation: C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H20(g) AH =-2046 kJ. If it takes 1.8 x 10° kJ to fully cook a rack of lamb on a gas barbeque, how many grams of propane will be required, assuming all the heat from the %3D combustion reaction is absorbed by the lamb? Give your answer to 2 significant figures, but not in scientific notation.
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