Question
Asked Sep 26, 2019
Q 14 Find the derivative of the function using the definition of derivative. State the domain of the
function and the domain of its derivative.
-3 + (2y)
b. g(s)= V9- x
h(y) =
a.
-2y + 2
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Q 14 Find the derivative of the function using the definition of derivative. State the domain of the function and the domain of its derivative. -3 + (2y) b. g(s)= V9- x h(y) = a. -2y + 2

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Step 1

Part (a)

Consider the given function.

-3 2y
hy)2y+2
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-3 2y hy)2y+2

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Step 2

On differentiating with respect to y, it gives

d
d
(-2y 2)3+2y)-(-3+2y)(2y2)
h'(y)=
(-2y+2)
h'(y)-2y+2) (0+2)-(-3+2y)(-2+0)
(2-2y)
h'(y)=4y+4- (6-4y)
(2-2y)
h'(y) =_y4-6+4y
(2-2y)
-2
h'(y)2-2y
-2
h'(y) 4(1-)
h'(y)=2(1-
1
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d d (-2y 2)3+2y)-(-3+2y)(2y2) h'(y)= (-2y+2) h'(y)-2y+2) (0+2)-(-3+2y)(-2+0) (2-2y) h'(y)=4y+4- (6-4y) (2-2y) h'(y) =_y4-6+4y (2-2y) -2 h'(y)2-2y -2 h'(y) 4(1-) h'(y)=2(1- 1

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Step 3

The domain of the given fu...

-2y 2 0
-2y
y1
Domain y Ry 1}
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-2y 2 0 -2y y1 Domain y Ry 1}

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Math

Calculus