Question
Asked Nov 14, 2019
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       The figure shows the interference pattern that appears on a distant screen when coherent light is incident on a mask with two identical, very narrow slits. Points P and Q are maxima; Point R is a minimum. The wavelength of the light that created the interference pattern is λ=678nm, the two slites are separated by rm d=6 μm, and the distance from the slits to the center of the screen is L=80cm . The difference in path length at a point on the screen is Δs=|s1−s2|, where s1s1 and s2s2 are the distances from each slit to the point.

 What is ΔsΔs (in nm) at Point P?

 What is ΔsΔs (in nm) at Point Q?

What is ΔsΔs (in nm) at Point R? 

 

Q R
P
Center of Screen
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Q R P Center of Screen

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Expert Answer

Step 1

The point P is at central maxima. Therefore, the path length “delta s” at point P will be zero.

Step 2

The point Q is at first maxima.

The formula for the position of the maxima is:

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mAL As d

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Step 3

For first maxima: m=1. ...

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(1)(678 nm)(80 cm) (6 Jum) As (10 m (1)(678 nm) nm (80 cm 100 cm 10 m (6 um) 100 cm (0.0904 m) 1m =9.4 cm

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Wave Optics

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