Q // The mechanism shown in the figure below has 0.02 in. gap at 80 Fahrenheit degree, find (a) the temperature at which the normal stress in the aluminum bar will be equal to 12 ksi (compression), (b) the corresponding final length of the aluminum bar. (10 mark) 0.02 in. -16 in - 20 in Bronze A - 2.4 in E = 15 x 10° psi a - 12 x 10-6/°F Aluminum A - 2.8 in E - 11 x 10 psi a - 13 x 10-j°F

Question
Q // The mechanism shown in the figure below has 0.02 in. gap at 80 Fahrenheit
degree, find (a) the temperature at which the normal stress in the aluminum bar
will be equal to 12 ksi (compression), (b) the corresponding final length of the
aluminum bar. (10 mark)
0.02 in.
-16 in
- 20 in
Bronze
A - 2.4 in
E = 15 x 10° psi
a - 12 x 10-6/°F
Aluminum
A - 2.8 in
E - 11 x 10 psi
a - 13 x 10-j°F
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Transcribed Image Text

Q // The mechanism shown in the figure below has 0.02 in. gap at 80 Fahrenheit degree, find (a) the temperature at which the normal stress in the aluminum bar will be equal to 12 ksi (compression), (b) the corresponding final length of the aluminum bar. (10 mark) 0.02 in. -16 in - 20 in Bronze A - 2.4 in E = 15 x 10° psi a - 12 x 10-6/°F Aluminum A - 2.8 in E - 11 x 10 psi a - 13 x 10-j°F

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