Q / The mechanism shown in the figure below has 0.02 in. gap at 80 Fahrenheit degree, find (a) the temperature at which the normal stress in the aluminum bar will be equal to 12 ksi (compression), (b) the corresponding final length of the aluminum bar. 0.02 in. -16 in 20 in Bronze A = 2.4 in E = 15 x 10° psi a = 12 x 10-6/°F Aluminum A = 2.8 in E = 11 × 10° psi a = 13 x 10-6°F

Q / The mechanism shown in the figure below has 0.02 in. gap at 80 Fahrenheit degree, find (a) the temperature at which the normal stress in the aluminum bar will be equal to 12 ksi (compression), (b) the corresponding final length of the aluminum bar. 0.02 in. -16 in 20 in Bronze A = 2.4 in E = 15 x 10° psi a = 12 x 10-6/°F Aluminum A = 2.8 in E = 11 × 10° psi a = 13 x 10-6°F

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.5.13P: Rectangular bars of copper and aluminum are held by pins at their ends, as shown in the figure. Thin...

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