q.4 An aluminum cup weighing 60.0 g is filled with 30.0 g of water. How much energy is needed to raise the temperature of the water filled cup from 20.0 to 22.5°C? (note that energy goes to both water AND cup)
Specific heat is the heat absorbed or released by one gram of a substance during change of one degree centigrade or one Kelvin temperature .
Or
Heat capacity is the heat absorbed or released by a substance during change of one degree centigrade or one Kelvin temperature.
Given:
Mass of water = 30.0 g.
Mass of aluminium cup = 60.0 g
Initial temperature of water = 20.0 0C.
Initial temperature of aluminium = 20.0 0C
Final temperature of both water and aluminium = 22.5 0C.
Formula used:
Q = ms ΔT
Where
Q = heat absorbed / released.
m = mass of substance.
s = specific heat of substance.
ΔT = temperature change.
We know that:
Specific heat of aluminium = 0.900 J/gm 0C
Specific heat of water = 4.184 J/gm 0C
As given that both aluminium and water will absorb heat to raise the temperature.
Let us calculate the heat needed by each
Heat needed by water:
Q1 = mass ...
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