Q30. Electric field intensity is equal to O time rate of change of potential O minimum rate of change of potential with distance O maximum rate of change of potential with distance O none of the above

Q30. Electric field intensity is equal to O time rate of change of potential O minimum rate of change of potential with distance O maximum rate of change of potential with distance O none of the above

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter7: Electric Potential

Section: Chapter Questions

Problem 37P: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104...

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Q30. Electric field intensity is equal to
time rate of change of potential
O minimum rate of change of potential with distance
O maximum rate of change of potential with distance
O none of the above

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A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electorn if the field strength is 2.50104 N/C. (b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole.
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