Q4] Find the equation of the tangent plane and normal line to the surface z + 8 = x e' cos z at point (8,0,0)
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- A plane area is bounded in the first quadrant by the curves y² = -16 (x-4), the line 8x-15y = 0, and the x-axis. What is the moment of inertia of this area about the line y = -10 ?A plane area is bounded in the first quadrant by the curves y² = -16 (x-4), the line 8x-15y = 0, and the x- axis. What is the moment of inertia of this area about the line y = -10 ?Find equations of (a) the tangent plane and (b) the normal line given to the surface at the specified point yz2 - ex-z = 0 (1, 1, 1)
- Find an equation for the tangent plane to the surfacez+4=xy4cos(z)z+4=xy4cos(z)at the point (4,1,0)(4,1,0)Find parametric equations for the normal line to the surfacez=ln(3x2 +7y2 +1) at the point (0,0,0)Find an equation of the tangent plane to the surface z = 16 − x2 − y2 at the given point (2, 2, 8) and find a set of symmetric equations for the normal line to the surface at the given point.
- ASAP PLZ Find the moment of inertia with respect to x-axis of the region in the first quadrant, which bounded by the curve y² =4x, the line y = 2 and the y-axis.The curve with parametric equationsx = t, y = 1 - cos t, 0 ≤ t ≤ 2πis called a sinusoid. Findthe point (x, y) where the slope of the tangent line is largest.3Express the square of the arc length differential on the surface z=xy. What does it take to find the shortest curve (geodesic) on this surface that reaches from point (1,1,1) to point(2,3,6)?
- Find the tangent plane to surface 8x2 + y2 + 4z2 = 25 at the point ( 1, -1, 2 ).Compute the equation of the tangent plane to the surface: y = 1 - x2 - 2z2 At the point (0, 1, 0)The curve with parametric equationsx = t, y = 1 - cos t, 0 ≤ t ≤ 2πis called a sinusoid. Findthe point (x, y) where the slope of the tangent line is smallest