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q5. If a sample of aluminum at 50.°C is added to 30.0 mL of water at 22.0°c, and at equilibrium thtemperature of the mixture was found to be 31.0°C, what was the mass of the aluminum?the

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q5. If a sample of aluminum at 50.°C is added to 30.0 mL of water at 22.0°c, and at equilibrium th
temperature of the mixture was found to be 31.0°C, what was the mass of the aluminum?
the
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q5. If a sample of aluminum at 50.°C is added to 30.0 mL of water at 22.0°c, and at equilibrium th temperature of the mixture was found to be 31.0°C, what was the mass of the aluminum? the

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Step 1

Mass of the aluminum is to be calculated when the following data is given-

Initial Temperature of the aluminum, Ti,Al = 50.0 º C

Final temperature of the mixture, Tf = 31.0 ºC

Volume of water = 30.0 mL

Initial temperature of water, Ti,w = 22.0º C

Step 2

This is a thermo- equilibrium situation. At the point of equilibrium, heat lost by the metal would be equal to the heat gained by the water. 

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Step 3

To calculate the heat gained by water, first determi...

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