
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:Question 1
The force of friction always acts in the opposite direction of motion of the object it is
acting on.
True
False
Question 2
The sum of all of the forces acting on a stationary object (v=0m/s), is the same as an
object traveling at a constant acceleration.
True
False
Question 3
As you increase the angle of a ramp, the normal force applied to the object by ramp
also increases.
True
False
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- Only two horizontal forces act on a 6.8 kg body. One force is 7.9 N, acting due east, and the other is 6.6 N, acting 40° north of west. What is the magnitude of the body's acceleration? Number i Unitsarrow_forwardProblem 3: Two children push horizontally on a third child who is sitting fixed in a wagon that has essentially frictionless wheels. The first child pushes in the positive x-direction with force of magnitude 70 N while the second child pushes in the negative x-direction with a force of magnitude 95 N. a) Draw a free-body diagram of the "child-in-the-wagon" system. b) If the child in the wagon has a mass of 40 kg and the wagon has a mass of 9 kg, what is the acceleration of the child in the wagon?arrow_forwardGOAL Apply the concept of static friction to an object resting on an incline. PROBLEM Suppose a block with a mass of 2.50 kg is resting on a ramp. If the coefficient of static friction between the block and ramp is ng sin e 0.350, what maximum angle can the ramp make with the horizontal mg cos e e before the block starts to slip down? STRATEGY This is an application of Newton's second law involving an object in equilibrium. Choose tilted coordinates, as in the figure. Use the fact that the block is just about to slip when the force of static friction takes its maximum value, f. = 4n. SOLUTION Write Newton's laws for a static system (1) EF = mg sin e - u̟n = 0 in component form. The gravity force (2) EF = n - mg cos e = 0 has two components. Rearrange Equation (2) to get an n = mg cos 8 expression for the normal force n. Substitute the expression for n into EF, = mg sin 8 - H mgcos 0 = 0 → tan 8 =u. Equation (1) and solve for tan 0. Apply the inverse tangent function to get the answer.…arrow_forward
- 30° P 20° A 30 kg package is at rest on an inclined plane when a force P is applied to it. Determine the magnitude of said force (in Newtons) if 15 s are required for the package to travel 7.5 m up the inclined plane. The coefficients of static and kinetic friction between the package and the inclined plane are equal to 0.3arrow_forwardA 2.80-kg object is moving in a plane, with its x and y coordinates given by x = 2t² - 4 and y = 2t³ + 3, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.45 s. 33 X If you know the position of an object as a function of time, you can calculate the acceleration as a function of time using calculus methods. Narrow_forwardTwo blocks are connected via a massless rope over a massless, frictionless pulley. Mass M = 10.7 kg, and mass m = 5.12 kg. If they both have a coefficient kinetic friction of 0.372 what will the magnitude of the acceleration of this system be? m 70 40 Units Numberarrow_forward
- A person of mass m= 80 kg pushes a fridge of mass M = 140 kg across a floor with a constant velocity in the +x hat direction. the interface between the floor and the fridge has coefficients of friction μs = 0.75 and μk= 0.35 What is the force exerted by the fridge on the person? F fridge --> person?arrow_forwardQUESTION 12 Two boxes (M1-1 kg. M2-2 kg) are adjacent to each other horizontally (NOT vertically stacked) on a frictionless floor, with Mi to the left of M2. A horizontal force of 12 N pushes on M1 towards the right a horizontal force of 18 N pushes on M2 towards the left. What is the magnitude of the force of M1 on M2? 12 N O 18 N O 14 N 2 N O NOTAarrow_forward
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