# Question 4 (25 points)Find reactions, max absolute shear force, max absolute bendingmoment, draw shear force and bending moment diagrams byMoment Distribution Method. (Given uniform loadings w1 = 1k/ft between A and B, w2 = 2 k/ft between B and C, w3 = 3 k/ftbetween C and D, and E= 29,000 ksi and I = 1170 in4)ADC=-25 ft30 ft-25 ftEl = constant%3D

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Find reactions, max absolute shear force, max absolute bending moment, draw shear force and bending moment diagrams by Moment Distribution Method. (Given uniform loadings w1 = 1 k/ft between A and B, w2 = 2 k/ft between B and C, w3 = 3 k/ft between C and D, and E= 29,000 ksi and I = 1170 in4 ) help_outlineImage TranscriptioncloseQuestion 4 (25 points) Find reactions, max absolute shear force, max absolute bending moment, draw shear force and bending moment diagrams by Moment Distribution Method. (Given uniform loadings w1 = 1 k/ft between A and B, w2 = 2 k/ft between B and C, w3 = 3 k/ft between C and D, and E= 29,000 ksi and I = 1170 in4) A D C= -25 ft 30 ft -25 ft El = constant %3D fullscreen
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Step 1

Calculating stiffness of beam: help_outlineImage Transcriptionclose4EI Stiffness of AB (Far end is fixed) 4x 29000x1170 25 = 5428800 k-ft/rad Stiffness of BA = 5428800 k-ft/rad 4EI Stiffness of BC = (Far end is fixed) 4x 29000×1170 30 = 4524000 k-ft/rad Stiffness of CB = 4524000 k-ft/rad 4EI Stiffness of CD =. (Far end is fixed) 4x 29000x1170 25 = 5428800 k-ft/rad Stiffness of DC = 5428800 k-ft/rad fullscreen
Step 2

Calculating fixed end moments of the given beam in different section of the beam:

Note: Considering intermediate support B and C as a fixed support. help_outlineImage TranscriptionclosewL MFAB 12 1× 25 12 =-52.08 k-ft MFBA 52.080 k-ft wL MFBC 12 2x30 12 =-150 k-ft Месв 150 k-ft MECD 12 3x 25? 12 =-156.25 k-ft MEDC =156.25 k-ft fullscreen
Step 3

Distribution Factor ... help_outlineImage TranscriptioncloseTotal Stiffness Joint Member Relative DF (k-ft'rad.) Stiffness (k-ft'rad.) 5428800 BA 5428800 = 0.54 9952800 B 9952800 4524000 = 0.46 BC 4524000 9952800 4524000 CB 4524000 = 0.46 9952800 5428800 9952800 5428800 0.54 CD 9952800 fullscreen

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