  # QUESTION 5Consider the reaction below at 100oC.  T2U  (g)   ->  2 T (g)   +  U (g)  If given an initial reactant concentration  [T2U]o = 0.250 M, what is [T] after 15 minutes have elapsed?    A.   0.486 M  B.   0.243 M  C.   0.00724 M  D.   0.121 M

Question

### QUESTION 5

 Consider the reaction below at 100oC.   T2U  (g)   ->  2 T (g)   +  U (g)   If given an initial reactant concentration  [T2U]o = 0.250 M, what is [T] after 15 minutes have elapsed?
 A.   0.486 M B.   0.243 M C.   0.00724 M D.   0.121 M
check_circleExpert Solution
Step 1

All you need to do is to solve the integrated rate law for the reactant concentration, and substitute

the given initial concentration and reaction time.

Integrated first order rate law is given by

If the rate constant is 8*10-4S-1

Step 2

After 15 mins ,the concentration of the reactant can be calculated as

ln[A] = ln[A]₀ - k∙t

=[A] = e^( ln[A]₀ - k∙t ) = e^(ln[A]₀) ∙e^(-k∙t ) = [A]₀ e^(-k∙t)

= [A] = ...

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### Chemistry 