Question asks: Nerve cells are long, thin cylinders along which electrical disturbances (nerve impulses) travel. The cell membrane of a typical nerve cell consists of an inner and an outer wall separated by a distance of 0.10 μm. The electric field within the cell membrane is 7.0×105N/C. Approximating the cell membrane as a parallel-plate capacitor, determine the magnitude of the charge density on the inner and outer cell walls.When solved through Bartleby, the distance is not used at all. Why is that and is there another way to solve the problem using the distance?

Question
Asked Jan 31, 2019
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Question asks: Nerve cells are long, thin cylinders along which electrical disturbances (nerve impulses) travel. The cell membrane of a typical nerve cell consists of an inner and an outer wall separated by a distance of 0.10 μm. The electric field within the cell membrane is 7.0×105N/C. Approximating the cell membrane as a parallel-plate capacitor, determine the magnitude of the charge density on the inner and outer cell walls.

When solved through Bartleby, the distance is not used at all. Why is that and is there another way to solve the problem using the distance?

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Expert Answer

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Step 1

For a parallel plate capacitor, the electric field E is given by,

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Step 2

On Re-arranging and substituting the values to get σ,

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Step 3

Electric field of a parallel plate capacitor is independent on the di...

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Electric Charges and Fields

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