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R1R2BA.C2200Q1kQV112 VV2.9 VV3R3560006 V...

Question

Find VAD, VB and VCE

R1
R2
B
A.
C
2200Q
1kQ
V1
12 V
V2
.9 V
V3
R3
56000
6 V
...
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R1 R2 B A. C 2200Q 1kQ V1 12 V V2 .9 V V3 R3 56000 6 V ...

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check_circleAnswer
Step 1

To find VAD:

From the given circuit,
VAD = VABVBC+9 V
(1)
ВС
Here
-(ov)
2200
AB=(9 V)
Ik-10
2200 1000 5600
-2.25 V
-(ov
1000
Ik-10'
BC
220010005600
=1.0227 V
Therefore, equation (1) becomes
VAD 2.25 V +1.0227 V +9 V
=12.2727 V
help_outline

Image Transcriptionclose

From the given circuit, VAD = VABVBC+9 V (1) ВС Here -(ov) 2200 AB=(9 V) Ik-10 2200 1000 5600 -2.25 V -(ov 1000 Ik-10' BC 220010005600 =1.0227 V Therefore, equation (1) becomes VAD 2.25 V +1.0227 V +9 V =12.2727 V

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Step 2

To find VB:

...
From the given circuit, node B is a grounded.
Therefore, voltage at node B is zero. That is, V 0 V
help_outline

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From the given circuit, node B is a grounded. Therefore, voltage at node B is zero. That is, V 0 V

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