reaction. Use wedge and dash bonds to indicate stereochemistry where appropriate. Ignore inorganic byproducts. Br2

grammarly-G X * Content oard.odu.edu/ultra/courses/_393452_1/cl/outline F2 Question Completion Status: X GA student wan X 1 QUESTION 3 A student wants to determine the solubility of water and copper (1) bromide (a green solid) in ethyl acetate (a colorless organic liquid). She places 1 mL of ethyl acetate into each of two test tubes. To one, she adds 5 drops of water to it. To the other, she adds a small scoop of copper(1) bromide. 8.0 F3 2 - Which test tube represents the ethyl acetate and A. Test tube 1 copper(1) bromide if the copper(1) bromide is insoluble in ethyl B. Test tube 2 acetate? C. Test tube 3 D. Test tube 4 - Which test tube represents the mixture of the ethyl acetate and water if the water is insoluble in ethyl acetate? $ Question Com X C Chegg Search x 3 Which test tube represents the mixture of the ethyl acetate and water if the water is soluble in ethyl acetate? - Which test tube represents the ethyl acetate and copper(1) bromide if the copper(1) bromide is soluble…

The Kjeldahl method was used to determine the nitrogen content of a protein. A 275 µL aliquot of a 47.0 mg/mL protein solution was digested in boiling sulfuric acid. The solution was made basic and the liberated NH, was collected in 5.00 mL of 0.0512 M HCl. A volume of 7.00 mL of 0.0174 M NaOH was required to react with the excess HCl. Calculate the weight percent of nitrogen in the protein. weight percent: wt% N

The equivalence point is defined as moles acid = moles base. So first, let's calculate the initial moles of base we used. molpase Mpase = Volsoiution Molarity base = 0.100 (M) Volume of solution= _50.00 mL Moles of base = _5.00 mmol So, we need 5.00 mmol of acid (titrant) to be delivered to the analyte. Since we know the molarity of the acid and moles of acid, we just need to solve for the volume of acid (titrant) to be added. molacid Voladded Macid Molarity acid = . 0.200 (M) Moles of acid = _5.00 (mmol) Volume of acid needed to reach equivalence point (mL)