Refer to Exercise 16 in Section 9.1. a) Use the Fisher LSD method to find a 95% confidence interval for the difference between the means for a diameter of 16 and a diameter of 36. b) Use the Tukey–Kramer method to determine which pairs of diameters, if any, differ at the 5% level.
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Refer to Exercise 16 in Section 9.1.
a) Use the Fisher LSD method to find a 95% confidence interval for the difference
between the means for a diameter of 16 and a diameter of 36.
b) Use the Tukey–Kramer method to determine which pairs of diameters, if any, differ at
the 5% level.
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- Refer to Exercise 18 in Section 9.1. a) Use the Fisher LSD method to find a 95% confidence interval for the difference between the means for annularly threaded and smooth shank nails. b) Use the Tukey–Kramer method to determine which pairs of nail types, if any, differ at the 5% level.Chapter 6, Section 5, Exercise 236 Use a t-distribution and the given matched pair sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distribution of the differences is relatively normal. Assume that differences are computed using d=x1-x2.Test H0 : μd=0 vs Ha : μd≠0 using the paired difference sample results x¯d=10.51, sd=11.6, nd=25. Give the test statistic and the p-value.Round your answer for the test statistic to two decimal places and your answer for the p-value to three decimal places.test statistic = Enter your answer; test statisticp-value = Enter your answer; p-value Give the conclusion using a 5% significance level. Reject H0. Do not reject H0.Chapter 6, Section 4-HT, Exercise 212 Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distributions are relatively normal.Test H0 : μT=μC vs Ha : μT<μC using the fact that the treatment group (T) has a sample mean of 8.6 with a standard deviation of 4.1 while the control group (C) has a sample mean of 11.2with a standard deviation of 3.4. Both groups have 25 cases. (a) Give the test statistic and the p-value.Round your answer for the test statistic to two decimal places and your answer for the p-value to three decimal places.test statistic = p-value = (b) What is the conclusion of the test at a 5% significance level? Reject H0. Do not reject H0.
- When the parameter and the sample size is equal to the parameter is being estimated, then the estimator is said to be _________________. a. Unbiased b. Consistent c. Regular d. EfficientAs a result of complaints from customers about delivery times, the manager at a pizza delivery service is ready to undertake a study to determine whether the average delivery time differs from the status quo of 30 minutes. State the null and alternative hypotheses.Chapter 6, Section 5, Exercise 234 Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d=x1-x2.A 99% confidence interval for μd using the paired data in the following table: Case 1 2 3 4 5 Treatment 1 23 28 30 25 29 Treatment 2 17 31 24 20 20 Give the best estimate for μd, the margin of error, and the confidence interval.Enter the exact answer for the best estimate, and round your answers for the margin of error and the confidence interval to two decimal places.best estimate = Enter your answer; best estimatemargin of error = Enter your answer; margin of errorThe 99% confidence interval is Enter your answer; The 99% confidence interval, value 1 to Enter your answer; The 99% confidence interval, value 2 .
- 1. Find the minimum sample size (n) you use to so that p is within a margin of error of 3% with a 95% confidence level when p ̂ and q ̂ are unknown.The National Institute of Mental Health published an article stating that in any two-year period, approximately 10.5percent of American adults suffer from depression or a depressive illness. Suppose that in a survey of 150 people in a certain town, eight of them suffered from depression or a depressive illness. If you were conducting a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population, what would the null and alternative hypotheses be?In Exercises 5–20, assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. (Note: Answers in Appendix D include technology answers based on Formula 9-1 along with “Table” answers based on Table A-3 with df equal to the smaller of n1 − 1 and n2 − 1.) Car and Taxi Ages When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distribution), he recorded the ages of randomly selected passenger cars and randomly selected taxis. The ages can be found from the license plates. (There is no end to the fun of traveling with the author.) The ages (in years) are listed below. We might expect that taxis would be newer, so test the claim that the mean age of cars is greater than the mean age of taxis.
- A researcher wishes to estimate, with 99% confidence, the population proportion of families who eat fast food at least once per week. Her estimate must be accurate within 5% of the population proportion.Find the minimum sample size needed, using a prior study that found that 16% of the respondents said they eat fast food four to six times per weekA simple random sample of heights of 6400Englishmen has a mean of 67.85 inches and SD 2.56 inches, while a simple random sample of heights of 1600 Australians has a mean of 68.55 inches and SD of 2.52 inches. D the data indicate that Australians are, on the average, taller than Englishmen?Recently, the annual number of driver deaths per 100,000 for the selected age groups was as follows: Age Number of Driver Deaths per 100,000 16–19 38 20–24 36 25–34 24 35–54 20 55–74 18 75+ 28 Use the 4 steps of hypothesis testing to see if the prediction is significant with a criteria of alpha=.05 on the following data For each age group, pick the midpoint of the interval for the X value. (For the 75+ group, use 80.)