Refer to Part B of Table 2.30 for the conditional distribution of the numbe network failures M given network age A. Let Pr (A = 0) = 0.5; that is, you your room 50% of the time. a. Compute the probability of three network failures, Pr (M = 3). b. Use Bayes' rule to compute Pr (A = 0|M = 3). c. Now suppose you work in your room one-fourth of the time, so Pr (4 (0) -0.25. Use Baves' rule to compute Pr(4-OLM. 3)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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2.28
Refer to Part B of Table 2.3 for the conditional distribution of the number of
network failures M given network age A. Let Pr (A = 0) = 0.5; that is, you work in
your room 50% of the time.
a. Compute the probability of three network failures, Pr (M = 3).
b. Use Bayes' rule to compute Pr (A = 0|M = 3).
c. Now suppose you work in your room one-fourth of the time, so
Pr (A = 0) = 0.25. Use Bayes' rule to compute Pr (A = 0|M = 3).
Transcribed Image Text:2.28 Refer to Part B of Table 2.3 for the conditional distribution of the number of network failures M given network age A. Let Pr (A = 0) = 0.5; that is, you work in your room 50% of the time. a. Compute the probability of three network failures, Pr (M = 3). b. Use Bayes' rule to compute Pr (A = 0|M = 3). c. Now suppose you work in your room one-fourth of the time, so Pr (A = 0) = 0.25. Use Bayes' rule to compute Pr (A = 0|M = 3).
Table 2.3
Joint and Conditional Distributions of Number of Wireless Connection Failures (M) and Network Age (A)
A. Joint Distribution
Old network (A = 0)
New network (A = 1)
Total
Pr (MA = 0)
M = 0
Pr (MA = 1)
0.35
0.45
B. Conditional Distributions of M given A
0.80
M = 0
0.70
0.90
M = 1
0.065
0.035
0.10
M = 1
0.13
0.07
M = 2
0.05
0.01
0.06
M = 2
0.10
0.02
M = 3
0.025
0.005
0.03
M = 3
0.05
0.01
M = 4
0.01
0.00
0.01
M = 4
0.02
0.00
Total
0.50
0.50
1.00
Total
1.00
1.00
Transcribed Image Text:Table 2.3 Joint and Conditional Distributions of Number of Wireless Connection Failures (M) and Network Age (A) A. Joint Distribution Old network (A = 0) New network (A = 1) Total Pr (MA = 0) M = 0 Pr (MA = 1) 0.35 0.45 B. Conditional Distributions of M given A 0.80 M = 0 0.70 0.90 M = 1 0.065 0.035 0.10 M = 1 0.13 0.07 M = 2 0.05 0.01 0.06 M = 2 0.10 0.02 M = 3 0.025 0.005 0.03 M = 3 0.05 0.01 M = 4 0.01 0.00 0.01 M = 4 0.02 0.00 Total 0.50 0.50 1.00 Total 1.00 1.00
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