References]a. An aqueous solution contains 3.55 g of iron(III) sulfate,Fe2 (SO4)3, per liter. What is the molarity ofFe2 (SO4)3?Molarity =Мb. When the compound dissolves in water, theFe+ ions and the2-SOO ions in the crystal go into the solution. What is the molar concentration of each ion in the solution?Molar concentrationM Fe3+M SO42Molar concentration5 item attempts remainingSubmit AnswerTry Another Version

Question
Asked Oct 20, 2019
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References]
a. An aqueous solution contains 3.55 g of iron(III) sulfate,
Fe2 (SO4)3, per liter. What is the molarity of
Fe2 (SO4)3?
Molarity =
М
b. When the compound dissolves in water, the
Fe+ ions and the
2-
SOO ions in the crystal go into the solution. What is the molar concentration of each ion in the solution?
Molar concentration
M Fe3+
M SO42
Molar concentration
5 item attempts remaining
Submit Answer
Try Another Version
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References] a. An aqueous solution contains 3.55 g of iron(III) sulfate, Fe2 (SO4)3, per liter. What is the molarity of Fe2 (SO4)3? Molarity = М b. When the compound dissolves in water, the Fe+ ions and the 2- SOO ions in the crystal go into the solution. What is the molar concentration of each ion in the solution? Molar concentration M Fe3+ M SO42 Molar concentration 5 item attempts remaining Submit Answer Try Another Version

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Expert Answer

Step 1

(a). Given,

Mass of iron(III) sulfate, Fe2(SO4)3 = 3.55 g

Volume of solution = 1 L

Moles of iron(III) sulfate, Fe2(SO4)3 can be calculated as:

Molar mass of Fe2(SO4)3 (2x55.8) 3[32+(4x16)]
399.6 g/mol
3.55 g
Mass
Moles
= 0.0088 mol
Molar mass
399.6 g/mol
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Molar mass of Fe2(SO4)3 (2x55.8) 3[32+(4x16)] 399.6 g/mol 3.55 g Mass Moles = 0.0088 mol Molar mass 399.6 g/mol

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Step 2

Molarity of Fe2(SO4)3 solution can be calculated as:

Moles
Molarity
Volume in litres
0.0088 mol
Molarity
1 L
Molarity 0.0088 mol/L = 0.0088 M
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Moles Molarity Volume in litres 0.0088 mol Molarity 1 L Molarity 0.0088 mol/L = 0.0088 M

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Step 3

(b). Given, when Fe2(SO4)3 dissolves in water Fe3+ ions and SO42- ions in the crystal go into the solution.

This can be written as a balanced reaction as :

Fe2(SO4)3 → 2 Fe3+ + 3 SO42-

1 mole of Fe2(SO4)3 gives 2 moles of Fe3+ and 3 moles of SO42-

Therefore, 0.0088 mol of Fe2(SO4)3 will give:

 2 × 0.0088 moles = 0.0176 moles of Fe3+ and

...
Moles
Molar concentration
Volume in litres
0.0176 mol
Molar concentration of Fe3
1L
Molar concentration of Fe3+ 0.0176 mol/L 0.0176 M
0.0264 mol
Molar concentration of SO42--
1 L
Molar concentration of SO42- = 0.0264 mol/L = 0.0264 M
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Moles Molar concentration Volume in litres 0.0176 mol Molar concentration of Fe3 1L Molar concentration of Fe3+ 0.0176 mol/L 0.0176 M 0.0264 mol Molar concentration of SO42-- 1 L Molar concentration of SO42- = 0.0264 mol/L = 0.0264 M

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