Researchers discover that 85% of people who have suffered a heart attack had periodontal disease (an inflammation of the gums). Only 29% of people that have not had a heart attack actually have periodontal disease. a. Suppose heart attacks are rare in a community, occurring with a 10% probability. What is the probability that someone has periodontal disease? b. What is the probability that a person with periodontal disease will have a heart attack?

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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Researchers discover that 85% of people who have suffered a heart attack had periodontal disease (an inflammation of the gums). Only 29% of people that have not had a heart attack actually have periodontal disease.

a. Suppose heart attacks are rare in a community, occurring with a 10% probability. What is the probability that someone has periodontal disease?

b. What is the probability that a person with periodontal disease will have a heart attack?

Expert Solution
Given

    P(heart attack )= 0.10P(no heart attack )= 1 - P(heart attack )                                = 1 -  0.10                              =  0.90Also,         P( disease|heart attack) = 0.85P( no disease|heart attack) = 1 -0.85                                               = 0.15And   P( disease|no heart attack ) = 0.29 P( no disease|no heart attack ) = 1 - 0.29                                                     = 0.71

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