Review | ConstantsWhen it is 133 m above the ground, a rockettraveling vertically upward at a constant 8.20 m/srelative to the ground launches a secondary rocketat a speed of 12.2 m/s at an angle of 59.0° abovethe horizontal, both quantities being measured byan observer sitting in the rocket. Air resistanceshould be ignored.Part EWhat maximum height above the ground does the secondary rocket reach? This is a standardprojectile motion problem but all quantities used in the formulas should be with respect to thereference frame, which in this case is the ground. So the initial position of the secondary rocketwith respect to the ground is the launch height. Max height occurs when the y component of thevelocity with respect to the ground is zero. Acceleration on the secondary rocket is -g. Use themost convenient of the kinematic equations the one that does not involve time.V ΑΣφ139Н-mPrevious Answers Request AnswerSubmit

Question
Asked Nov 22, 2019
28 views

I don't understand how to find the height. I had gotten 139 m as my answer but it is not correct.

Review | Constants
When it is 133 m above the ground, a rocket
traveling vertically upward at a constant 8.20 m/s
relative to the ground launches a secondary rocket
at a speed of 12.2 m/s at an angle of 59.0° above
the horizontal, both quantities being measured by
an observer sitting in the rocket. Air resistance
should be ignored.
Part E
What maximum height above the ground does the secondary rocket reach? This is a standard
projectile motion problem but all quantities used in the formulas should be with respect to the
reference frame, which in this case is the ground. So the initial position of the secondary rocket
with respect to the ground is the launch height. Max height occurs when the y component of the
velocity with respect to the ground is zero. Acceleration on the secondary rocket is -g. Use the
most convenient of the kinematic equations the one that does not involve time.
V ΑΣφ
139
Н-
m
Previous Answers Request Answer
Submit
help_outline

Image Transcriptionclose

Review | Constants When it is 133 m above the ground, a rocket traveling vertically upward at a constant 8.20 m/s relative to the ground launches a secondary rocket at a speed of 12.2 m/s at an angle of 59.0° above the horizontal, both quantities being measured by an observer sitting in the rocket. Air resistance should be ignored. Part E What maximum height above the ground does the secondary rocket reach? This is a standard projectile motion problem but all quantities used in the formulas should be with respect to the reference frame, which in this case is the ground. So the initial position of the secondary rocket with respect to the ground is the launch height. Max height occurs when the y component of the velocity with respect to the ground is zero. Acceleration on the secondary rocket is -g. Use the most convenient of the kinematic equations the one that does not involve time. V ΑΣφ 139 Н- m Previous Answers Request Answer Submit

fullscreen
check_circle

Expert Answer

Step 1

The velocity relative to the observer sitting in the rocket is

-[(12.2m/s)cos 59.0Ji-[(122m/s)sin 59]i
(6.283m/s)i (10.457m/s)j
help_outline

Image Transcriptionclose

-[(12.2m/s)cos 59.0Ji-[(122m/s)sin 59]i (6.283m/s)i (10.457m/s)j

fullscreen
Step 2

The velocity relative to the observer on the ground is

=1
1
srw
-1
-[12.2m/s)cos 59.0]i+[12.2m/s)sin 59°(8.20m/s)]i
(6.283m/s)i+(18.657m/s)j
help_outline

Image Transcriptionclose

=1 1 srw -1 -[12.2m/s)cos 59.0]i+[12.2m/s)sin 59°(8.20m/s)]i (6.283m/s)i+(18.657m/s)j

fullscreen
Step 3

The horizontal and vertical components of it...

6.28m/s
=18.657m/s
1
help_outline

Image Transcriptionclose

6.28m/s =18.657m/s 1

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Advanced Physics

Related Advanced Physics Q&A

Find answers to questions asked by student like you

Show more Q&A add
question_answer

Q: Eventually, space telescopes have shown that Venus is shrouded by a very dense atmosphere (see Figur...

A: The information about the surface of the Venus is gathered mostly from the radar imaging technique. ...

question_answer

Q: Which one of the followings is a source of electromagnetic waves?   A) stationary electric charge...

A: Electromagnetic waves consist of electric and magnetic field oscillating perpendicular to each other...

question_answer

Q: 1

A: It is asked to proave the mean value theorem.

question_answer

Q: This is a problem in the field of quantum mechanics.

A: Write the given expression and multiply with both sides.

question_answer

Q: 3E0, and uHo) and for two 4. For uniform plane wave propagation in (i) ice (o 106 S/m, 8 (ii) seawat...

A: Write the expression for attenuation constant, phase constant, wavelength, skin depth and velocity

question_answer

Q: A ball is thrown straight up into the air. At what position is its kinetic energy a maximum? At what...

A: when a ball thrown upward, its speed will decrease at the rate of gravitational acceleration (Neglec...

question_answer

Q: What property of an object is a measurement of its thermal energy?

A: Thermal energy is due to the random motion of atoms, molecules or ions in a substance. So, thermal e...

question_answer

Q: The diameter of the Moon is 3500 km. On Figure 2 it is scaled down to 13.2 cm. What is the diameter ...

A: Given:Diameter of the moon,D = 1300 kmMeasure of the diameter on the scale of figure, d = 13.2 cmDia...

question_answer

Q: A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river. The rive...

A: Click to see the answer