Question

Asked Mar 18, 2019

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Step 1

Let player 1 moving in + x direction and player 2 at 140^{0} , the velocity of player 2 can be divided into two perpendicular components. The momentum of the player 1 in y-direction is zero. The conservation of momentum along x direction is shown in equation (1).

Step 2

Substitute 5.22meter per sec for v.

Step 3

Let the momentum conserved in y-direction, ...

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