Question
Asked Oct 11, 2019
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Refering to 5.79

Roll two more dice
Refer to the previous exercise.
5.80
5
Define event D as rolling an odd sum with two dice.
a. B denotes a sum of 7 on the two dice. Find P(B and D).
When an event B is contained within an event D, as
here, explain why P(B and D) P(B).
b. Find P(B or D). When an event B is contained within
an event D, explain why P(B or D) = P(D).
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Roll two more dice Refer to the previous exercise. 5.80 5 Define event D as rolling an odd sum with two dice. a. B denotes a sum of 7 on the two dice. Find P(B and D). When an event B is contained within an event D, as here, explain why P(B and D) P(B). b. Find P(B or D). When an event B is contained within an event D, explain why P(B or D) = P(D).

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Expert Answer

Step 1

As per the question

Event D-> rolling an odd sum with two dice

Events in D include sum of 3,5,7,9,11

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3(1,2), (2,1) 5 (1,4), (2,3), (3,2), (4,1) D =7(1,6), (2,5), (3,4), (4,3), (5,2), (6,1) 9 (3,6), (4,5), (5,4), (6,3) 11 (5,6), (6,5)

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Step 2

a)

Event B denotes a sum of 7 on the two...

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B (7(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)} B and D means B intersection D i.e Р(В апd D) — Р (Вn D) => BnD= {7- (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)} В => P(B and D) P(Bn D) = P(B)

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