Question
Asked Oct 23, 2019
RON
GN
Ms-0.75
Hs0.75
30°
Req'd: Normal FOrce oF 2ON
frictional FOT ce OF 30 N
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RON GN Ms-0.75 Hs0.75 30° Req'd: Normal FOrce oF 2ON frictional FOT ce OF 30 N

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Step 1

Sketch the Free Body Diagram as shown in Figure.

30°
36 N 20 N M
30°
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30° 36 N 20 N M 30°

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Step 2
Step 3

Find the normal force of 20 N and frictio...

Normal Force of 20 N(N,) = 20 cos 30
=17.32 N
Normal Force of 36 N(N,) = 36cos 30°
=31.18 N
Friction al Force of 36 N(f)= N
=0.75x31.18
= 23.385 N
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Normal Force of 20 N(N,) = 20 cos 30 =17.32 N Normal Force of 36 N(N,) = 36cos 30° =31.18 N Friction al Force of 36 N(f)= N =0.75x31.18 = 23.385 N

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