Is the following answer correct? The given state of certain gas is,RT .(а+bT)P = +V.V„RT +(a+bT)Now differentiate the above expression as follows:dPdTd (VRT +(a+bT)|= 0dTv?d:(V„T)R+.dTddr(a+bT)-(V„RT +(a+bT)) (v;)|dTdT= 0dV= 0dTdVRTm+V„R +b -(VmRT +(a+bT)) 2V,dTdV,RT- 2VRT – 2V„a-2V„bT)+VR+Vb=0dTdV(VRT +2Va+ 2V„bT)=V R+VbdTVR+V?bdT (VRT+2V„a+2V„bT)vR+V„b(V„RT +2a+2bT)dVm'dT RT2) The equation of state of a certain gas is given by p =Vma+bTwhere a and b are constants. Find(A),ƏT

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RT a+bT 2) The equation of state of a certain gas is given by p = + where a andb are constants. Find Vm ), ƏT

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter2: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 2.43E

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Question

Is the following answer correct?

The given state of certain gas is,
RT .(а+bT)
P = +
V.
V„RT +(a+bT)
Now differentiate the above expression as follows:
dP
dT
d (VRT +(a+bT)
|= 0
dT
v?
d
:(V„T)R+.
dT
d
d
r(a+bT)-(V„RT +(a+bT)) (v;)|
dT
dT
= 0
dV
= 0
dT
dV
RT
m
+V„R +b -(VmRT +(a+bT)) 2V
,
dT
dV,
RT- 2VRT – 2V„a-2V„bT)+VR+Vb=0
dT
dV
(VRT +2Va+ 2V„bT)=V R+Vb
dT
VR+V?b
dT (VRT+2V„a+2V„bT)
vR+V„b
(V„RT +2a+2bT)
dV
m'
dT

RT
2) The equation of state of a certain gas is given by p =
Vm
a+bT
where a and b are constants. Find
(A),
ƏT

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