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srise/A*4w15. A pipe has a 35 degree bend that is 3-1/4 incheslong. Calculate x and y, the horizontal andvertical components of the bend, rounded tothe nearest 16th of an inch.3-1/4"35°X16. Challenge Problem: Assuming you weresuccessful with the previous question, calculatethe short length of the bend in the 2-1/4 inch2-1/4"diamet

Question
A pipe has a 35 degree bend that is 3-1/4 inches long
s
rise/
A*
4
w
15. A pipe has a 35 degree bend that is 3-1/4 inches
long. Calculate x and y, the horizontal and
vertical components of the bend, rounded to
the nearest 16th of an inch.
3-1/4"
35°
X
16. Challenge Problem: Assuming you were
successful with the previous question, calculate
the short length of the bend in the 2-1/4 inch
2-1/4"
diamet
help_outline

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s rise/ A* 4 w 15. A pipe has a 35 degree bend that is 3-1/4 inches long. Calculate x and y, the horizontal and vertical components of the bend, rounded to the nearest 16th of an inch. 3-1/4" 35° X 16. Challenge Problem: Assuming you were successful with the previous question, calculate the short length of the bend in the 2-1/4 inch 2-1/4" diamet

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check_circleAnswer
Step 1

From the given figure,

sin35°
y=3_xsin35°
4
13
-xsin35°
4
3.25x0.57357
y1.8641
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sin35° y=3_xsin35° 4 13 -xsin35° 4 3.25x0.57357 y1.8641

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Step 2

Round the answer to the nearest 16th of an inch as follows.

y 1+0.8641
16
1+0.8641x-
16
13.8256
=1+
16
14
16
7
1inches or 1- inches
8
14
16
inches
Thus, the vertical component of the bend is 1
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y 1+0.8641 16 1+0.8641x- 16 13.8256 =1+ 16 14 16 7 1inches or 1- inches 8 14 16 inches Thus, the vertical component of the bend is 1

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Step 3

From the given ...

х
cos35°
1
3
4
x 3-xcos35°
4
13
-x cos3 5°
4
3.25 x0.819 15
y 2.6622
help_outline

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х cos35° 1 3 4 x 3-xcos35° 4 13 -x cos3 5° 4 3.25 x0.819 15 y 2.6622

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