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s = (x, y) x 2 2, 0 < y se

Question

Sketch the region attached with the question. 
Find its area (if the area is finite).  Do nothing else if it is infinite.

s = (x, y) x 2 2, 0 < y se
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s = (x, y) x 2 2, 0 < y se

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Step 1

Consider the function:

x22
Here, xE 2, )
Consider the function y = e *
Which cut the y- axis at (0,1)
The common region of both above the function lies in the interval 2
)
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x22 Here, xE 2, ) Consider the function y = e * Which cut the y- axis at (0,1) The common region of both above the function lies in the interval 2 )

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Step 2

on further calculation

) and y lies in the interval 0 e
x 2 provides the region x E 2
so the common region will liein x E 2
),
between x = 2 to x = 0 and y = e
So we have to integrate the function e* fromx = 2 to x = 0o.
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) and y lies in the interval 0 e x 2 provides the region x E 2 so the common region will liein x E 2 ), between x = 2 to x = 0 and y = e So we have to integrate the function e* fromx = 2 to x = 0o.

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Step 3

On Integrat...

1
fe dt=-e
2
-HH
1
1
1
+1]
1
sq.unit
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1 fe dt=-e 2 -HH 1 1 1 +1] 1 sq.unit

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Tagged in

Math

Calculus

Integration

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