Sample size (n) is 16, mean of the sample means (x¯¯) is 15, mean of the sample ranges (R¯)is 6, and population standard deviation is not known. Calculate the UCL and LCL of the mean chart for this process, by using 3-sigma (z=3).nA2D3D421.8800.0003.26731.0230.0002.57540.7290.0002.28250.5770.0002.11460.4830.0002.00470.4190.0761.92480.3730.1361.86490.3370.1841.816100.3080.2231.777110.2850.2561.744120.2660.2831.717130.2490.3071.693140.2350.3281.672150.2230.3471.653160.2120.3631.637170.2030.3781.622180.1940.3911.609UCL=13.73, LCL=16.27Cannot be calculatedUCL=12.5, LCL=11.0UCL = 10.34, LCL = 13.67UCL = 16.27, LCL = 13.73

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Description: Sample size (n) is 16, mean of the sample means (x¯¯) is 15, mean of the sample ranges (R¯)is 6, and population standard deviation is not known. Calculate the UCL and LCL of the mean chart for this process, by using 3-sigma (z=3).nA2D3D421.8800.0003.

Given: X=15, R=6, n=16 For n=16, the value of constant A2=0.212 The control limits of X chart is…

Answered: Sample size (n) is 16, mean of the…

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Author:Amos Gilat

Publisher:Amos Gilat

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Sample size (n) is 16, mean of the sample means (x¯¯) is 15, mean of the sample ranges (R¯)is 6, and population standard deviation is not known. Calculate the UCL and LCL of the mean chart for this process, by using 3-sigma (z=3).

n	A2	D3	D4
2	1.880	0.000	3.267
3	1.023	0.000	2.575
4	0.729	0.000	2.282
5	0.577	0.000	2.114
6	0.483	0.000	2.004
7	0.419	0.076	1.924
8	0.373	0.136	1.864
9	0.337	0.184	1.816
10	0.308	0.223	1.777
11	0.285	0.256	1.744
12	0.266	0.283	1.717
13	0.249	0.307	1.693
14	0.235	0.328	1.672
15	0.223	0.347	1.653
16	0.212	0.363	1.637
17	0.203	0.378	1.622
18	0.194	0.391	1.609

UCL=13.73, LCL=16.27

Cannot be calculated

UCL=12.5, LCL=11.0

UCL = 10.34, LCL = 13.67

UCL = 16.27, LCL = 13.73

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