Scientists are looking at the effects of global warming on clutches of sea turtle hatchlings in different parts of the world. The data below has been collected: 1.Temperature of Incubation (in Kelvin) 2. Gender Group of Hatchling Clutch (0=0% male; 1= greater than 0% but less than or equal to 10% male; 2= greater than 10% but less than 20% male; 3= greater than 20% but less than or equal to 30% male and so on) 3. Number of hatched eggs

The National Institute of Standard and Technology provided exact data on conductivity properties of materials. Following are conductivity measurements for 11 randomly selected pieces of a particular type of glass. Click this button to reveal the data Conductivtity 1.11 1.07 1.11 1.07 1.12 1.08 0.98 0.98 1.02 0.95 0.95 Download CSV file Download the .csv file or copy/paste the data into Excel. After downloading .csv file, you may want to save it as a Excel Workbook. Based on these data, is there evidence that the median conductivity of this type of glass is greater than 1? Use a 10% level of significance level. a. How many samples of data are there in this study? b. What test you would use for this problem? Select an answer c. The null hypothesis of this test states that Select an answer d. What type of test is this? O One-side Two-side

Steele Industries has decided to use an R-Chart to monitor the changes in the variability of their 86.0086.00 pound metal shafts. The production manager randomly samples 77 metal shafts and measures the weight of the sample (in pounds) at 1818 successive time periods. Table Control Chart Copy Table Step 1 of 7 :   What is the Center Line of the control chart? Round your answer to three decimal places. Period    obs1    obs2    obs3    obs4    obs5    obs6    obs7    Sample Range1    86.03    85.98    86.05    86.03    85.97    85.96    86.03    0.092    86.05    86.05    86.01    86.05    86.00    85.98    86.00    0.073    86.01    86.04    86.04    85.97    85.99    86.00    86.01    0.074    85.96    85.99    86.00    85.96    86.05    86.00    86.03    0.095    86.03    85.99    86.02    85.96    85.96    86.04    86.00    0.086    85.96    86.03    85.96    85.97    85.98    86.02    86.05    0.097    86.05    86.04    86.05    85.99    85.96    85.98    86.02    0.098    85.99…

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15% pike. Five years later it sampled the lake to see if the distribution of fish had changed. It found that the 500 fish in the sample were distributed as follows. Catfish Bass Bluegill Pike 122 75 222 81 In the 5-year interval, did the distribution of fish change at the 0.05 level   Find the value of the chi-square statistic for the sample.   Estimate the P-value of the sample test statistic. P-value > 0.100 0.050 < P-value < 0.100     0.025 < P-value < 0.050 0.010 < P-value < 0.025 0.005 < P-value < 0.010 P-value < 0.005   Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories? Since the P-value > α, we fail to reject the null hypothesis. Since the P-value > α, we reject the null hypothesis.     Since the…