Sequence A AC GAATTC (EcoRI) NNNN... Sequence Probability Calculation Length 1 2 6 n 1/4 = (1/4)¹= 0.25 1/4*4 = (1/4)2 = 0.0625 1/4*14*14*14*14*1/4 = (1/4)6 = 2.44 x 10-4 14*14*14*... (1/4) Predicted Occurrence in a Sequence the Length of the Human Genome (3,234,830,000 bases) 808,707,500 202,176,875 89,753 (1/4)n* 3,234,830,000 Focus questions A. What is the probability that any base in a sequence is an adenine, A? How many times do you expect to find adenine in the human genome? P(A)= .25 808,707,500 times = expected occurrance of A B. What is the probability of finding a particular two-base sequence? How many times do you expect to find that sequence in the human genome? P(2-base seq) = . 0625 202, 176,875 times = expected occurrance of sequence C. How many times would you expect to find an EcoRI cut site in a fragment of DNA 1,000,000 base pairs long?

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter19: Genomes And Proteomes
Section: Chapter Questions
Problem 1ITD: Below is a sequence of 540 bases from a genome. What information would you use to find the...
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Sequence
A
AC
GAATTC (EcoRI)
NNNN...
Sequence Probability Calculation
Length
1
2
6
n
1/4 = (1/4)1 = 0.25
14*4 = (1/4)² = 0.0625
1⁄4*14*¹4*14*14*1 = (1/4)6 = 2.44 x 10-4
14*14*14*...= (1/4)
Predicted Occurrence in a
Sequence the Length of the Human
Genome (3,234,830,000 bases)
808,707,500
202,176,875
89,753
(1/4) * 3,234,830,000
Focus questions
A. What is the probability that any base in a sequence is an adenine, A? How many times do
you expect to find adenine in the human genome?
P(A) = .25
808, 707,500 times = expected
occurrance of A
B. What is the probability of finding a particular two-base sequence? How many times do you
expect to find that sequence in the human genome?
P(2-base seq) = . 0625
202, 176,875 times = expected
occurrance of sequence
C. How many times would you expect to find an EcoRI cut site in a fragment of DNA
1,000,000 base pairs long?
Transcribed Image Text:Sequence A AC GAATTC (EcoRI) NNNN... Sequence Probability Calculation Length 1 2 6 n 1/4 = (1/4)1 = 0.25 14*4 = (1/4)² = 0.0625 1⁄4*14*¹4*14*14*1 = (1/4)6 = 2.44 x 10-4 14*14*14*...= (1/4) Predicted Occurrence in a Sequence the Length of the Human Genome (3,234,830,000 bases) 808,707,500 202,176,875 89,753 (1/4) * 3,234,830,000 Focus questions A. What is the probability that any base in a sequence is an adenine, A? How many times do you expect to find adenine in the human genome? P(A) = .25 808, 707,500 times = expected occurrance of A B. What is the probability of finding a particular two-base sequence? How many times do you expect to find that sequence in the human genome? P(2-base seq) = . 0625 202, 176,875 times = expected occurrance of sequence C. How many times would you expect to find an EcoRI cut site in a fragment of DNA 1,000,000 base pairs long?
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