Show all your work for marks and report your answer to the correct number of significant figures. ((0.08376)x (2.539 x 10)) – ((3.5917 x 10²) + (4.683 x 10°)) (21.8+12.376) ((283 x 10-3) + (0.489 x 10–1 ))

Show all your work for marks and report your answer to the correct number of significant figures. ((0.08376)x (2.539 x 10)) – ((3.5917 x 10²) + (4.683 x 10°)) (21.8+12.376) ((283 x 10-3) + (0.489 x 10–1 ))

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.2: Trigonometric Equations

Problem 71E

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Question

100%

Show all your work for marks and report your answer to the correct number of
significant figures.
((0.08376)x (2.539 x 10)) – ((3.5917 x 10²) + (4.683 x 10°))
(21.8+12.376)
((283 x 10-3) + (0.489 x 10–1 ))

Expert Solution

Step 1

The given problem is

$\frac{((0.08376) \times (2.539 \times 10^{3})) - ((3.5917 \times 10^{2}) + (4.683 \times 10^{3}))}{\frac{(21.8 + 12.376)}{((2.83 \times 10^{- 3}) + (0.489 \times 10^{- 1}))}}$

Now we solve this to the correct number of significant figures.

$\frac{((0.08376) \times (2.539 \times 10^{3})) - ((3.5917 \times 10^{2}) + (4.683 \times 10^{3}))}{\frac{(21.8 + 12.376)}{((2.83 \times 10^{- 3}) + (0.489 \times 10^{- 1}))}}$

$=$ $\frac{((0.08376) \times (2539)) - ((359.17) + (4683))}{\frac{(21.8 + 12.376)}{((2.83 \times 10^{- 3}) + (0.489 \times 10^{- 1}))}}$

$=$ $\frac{((0.08376) \times (2539)) - ((359.17) + (4683))}{\frac{34.176}{((2.83 \times 10^{- 3}) + (0.489 \times 10^{- 1}))}}$

$=$ $\frac{((0.08376) \times (2539)) - ((359.17) + (4683))}{\frac{34.176}{((0.00283) + (0.0489))}}$

$=$ $\frac{(212.66664) - (5042.17)}{\frac{34.176}{(0.05173)}}$

$=$ $\frac{(212.66664) - (5042.17)}{660.6611251}$

$=$ $\frac{- 4829.50336}{660.6611251}$

$=$ $- 7.310106765$

=-7.31

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