Show that the function has local extreme values at the given values of 0 and say which kind of local extrema the function has.24.h(0) 4 cos0s0s 2T, 0 = 0 and 0 2xFind h'(0)h'(0)Set h'(0) equal to 0 and solve for 0 on 0s0s 2.Ө-(Type an exact answer, using t as needed. Use a comma to separate answers as needed.)Өhas local extreme values at 02on 0 s0 s 2n.Thus, h(0) 4 cos(Type an exact answer, using t as needed. Use a comma to separate answers as needed.)Evaluate h(0) at 0 and 2t.h(0)(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)h(21)(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)Determine which kind of local extrema the function has at 0 0 and 0 27tat 0 2TThe function has a local (1)at 0 0 and a local (2)|(1)(2)minimummaximummaximumminimum

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Asked Oct 28, 2019
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Show that the function has local extreme values at the given values of 0 and say which kind of local extrema the function has.
24.
h(0) 4 cos
0s0s 2T, 0 = 0 and 0 2x
Find h'(0)
h'(0)
Set h'(0) equal to 0 and solve for 0 on 0s0s 2.
Ө-
(Type an exact answer, using t as needed. Use a comma to separate answers as needed.)
Ө
has local extreme values at 0
2
on 0 s0 s 2n.
Thus, h(0) 4 cos
(Type an exact answer, using t as needed. Use a comma to separate answers as needed.)
Evaluate h(0) at 0 and 2t.
h(0)
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
h(21)
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
Determine which kind of local extrema the function has at 0 0 and 0 27t
at 0 2T
The function has a local (1)
at 0 0 and a local (2)
|(1)
(2)
minimum
maximum
maximum
minimum
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Show that the function has local extreme values at the given values of 0 and say which kind of local extrema the function has. 24. h(0) 4 cos 0s0s 2T, 0 = 0 and 0 2x Find h'(0) h'(0) Set h'(0) equal to 0 and solve for 0 on 0s0s 2. Ө- (Type an exact answer, using t as needed. Use a comma to separate answers as needed.) Ө has local extreme values at 0 2 on 0 s0 s 2n. Thus, h(0) 4 cos (Type an exact answer, using t as needed. Use a comma to separate answers as needed.) Evaluate h(0) at 0 and 2t. h(0) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) h(21) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) Determine which kind of local extrema the function has at 0 0 and 0 27t at 0 2T The function has a local (1) at 0 0 and a local (2) |(1) (2) minimum maximum maximum minimum

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Expert Answer

Step 1

Given,

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ө h(0)4 cos- 4 cos 2

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Step 2

The derivative of the function is

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ө d 4 cos h'(0) de 2 ө =4- cOS cos- de 2 ө) d (0 =-4sin 2 de 2 ө =-4sin 22 ө h'(0)= -2sin 2

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Step 3

Take the derivative is...

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ө -2sin = 0 2 ө sin 2 ө | sin () nZ sin 2 ө пт, пеZ 2 —0-2пт, пеZ 0 0,27 for n=0,1

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Math

Calculus

Functions