Show that there exists root in the interval [1, 2] of x = 2sin(x), and then use false position method to find this root with &s = 0.1%

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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3) Show that there exists root in the interval [1, 2] of x = 2sin(x),
and then use false position method to find this root with ɛs
0.1%
Transcribed Image Text:3) Show that there exists root in the interval [1, 2] of x = 2sin(x), and then use false position method to find this root with ɛs 0.1%
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