Showing L is not a limit We can prove that lim, f(x) # L by pro- viding an ɛ > 0 such that no possible 8 > 0 satisfies the condition |f(x) – L| < e whenever 0 < |x - c| < 8. We accomplish this for our candidate ɛ by showing that for each & > 0 there exists a value of x such that 0 < |x - c| < 8 |f(x) – L| 2 e. and y=f(x) L+e L-E fx). 0 c-8 c c+8 A value of x for which 0<|x-c| <ô and| f(x) – L| 2 8

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Showing L is not a limit We can prove that lim, f(x) # L by pro-
viding an ɛ > 0 such that no possible 8 > 0 satisfies the condition
|f(x) – L| < e whenever 0 < |x - c| < 8.
We accomplish this for our candidate ɛ by showing that for each & > 0
there exists a value of x such that
0 < |x - c| < 8
|f(x) – L| 2 e.
and
y=f(x)
L+e
L-E
fx).
0 c-8 c
c+8
A value of x for which
0<|x-c| <ô and| f(x) – L| 2 8
Transcribed Image Text:Showing L is not a limit We can prove that lim, f(x) # L by pro- viding an ɛ > 0 such that no possible 8 > 0 satisfies the condition |f(x) – L| < e whenever 0 < |x - c| < 8. We accomplish this for our candidate ɛ by showing that for each & > 0 there exists a value of x such that 0 < |x - c| < 8 |f(x) – L| 2 e. and y=f(x) L+e L-E fx). 0 c-8 c c+8 A value of x for which 0<|x-c| <ô and| f(x) – L| 2 8
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