sin 5x. lim X0 5x. Cos 5x

Q: 2 cos(4x) – 4x2 – 2 lim - I→0 sin(2x)- x2 - 2x

A: We have to evaluate the limit limx→0 2 cos(4x) - 4x2 - 2sin(2x) - x2 - 2x

Q: 1 lim (x² –1)sin x+1

A: To find out the limit.

Q: 5. x sin 3) lim00 x+1

A: limx→∞x5sin5xx4+1=limx→∞ x5sin5xx41+1x4= limx→∞ x sin5x1+1x4 = limx→∞  sin5x1x1+1x4=limx→∞ 5…

Q: 2. f(x) = sin(x) lim sin(x) - et x + 00

A: Calculate the limit and horizontal asymptote in the following way: (2).              f(x) = e-xsinx…

Q: lim (cos(9x)) (+) +0+x

A:

Q: 1+sin x lim

A: Given that,  limx→∞ 1+sin xx To evaluate  limx→∞ 1+sin xx=limx→∞ 1x+sin xx=limx→∞ 1x+limx→∞sin xx=0…

Q: x łan 5x sin? (2x) lim

A:

Q: lim x-->0 (sin(2x^3))/(3x^2)

A:

Q: x sin 4x b. lim x-0 1-cos3x

A:

Q: cos(1/x) 5. lim (1/x)

A: Find limx→∞ cos1x1x

Q: sin? (V6x) – x sin(6x) lim x→0

A: Limit at x=0 is 24

Q: -1 sin (5x) lim

A: The given expression is limx→0sin-15xx the given expression is the indeterminate form 00 Apply L'…

Q: 1 2. Lim x0x 1 sin x

A: Given:      limx→0+1x-1sinx simplifying we get     =limx→0+sinx-xxsinx Apply L'Hospital's Rule:…

Q: x sin(3x) lim x→0 sin(x2)

A:

Q: sin x cos 4x 32) lim X0 X+X cos 5x

A: Consider the given limit

Q: - 2 lim c. x→o Sin(x)

A: It is given that X approaching 0 from the left, X<0. Therefore, Sin(x)<0. Therefore, the…

Q: et - e- е limr0 2 sin x

A:

Q: 2 sin? x lim х-0 5x(1+сos x)

A: Let L=limx→ 02sin2x5x1+cosxlimx→ac·fx=c·limx→afxL=25limx→ 0sin2xx1+cosxPlug in the value…

Q: 44. lim sin² x x→n/4

A:

Q: x+2 lim sin - x+6x+8 3 2.

A:

Q: sin°(,² – 4) (x+2) tan(x+ 2 limy→-2

A: We have to solve

Q: x. 200 sin 3x 43. lim x0 5x - 4x

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: tan (3x) lim x→0 sin (2x)

A: Given query is to find the limit of the expression.

Q: sin(3x – 3) lim x² – 1

A: Given :

Q: x2 – lim x + sin x 2x x→0

A:

Q: Find the limits

A: Find the limit limx→-πx+4cosx+π

Q: x + sin 2x lim x-2 x – sin 2x О з O 2 O 1/3 О 12 O other:

A:

Q: 4x(1 — сos(x)) lim х — sin(x) х>0

A: Because the limit is in 0/0 form. Apply L'hopital's rule.

Q: 2 lim(cosx)x² =? x→0

A: Given: limx→0cosx2x2=limx→0cos2x2x

Q: 2 sin x 1 lim is

A:

Q: sin(9x) (d) lim x – 7 (e) lim 7| (f) lim x8, COS

A: We have to evaluate the following limits

Q: tan nx 3) lim x→0

A:

Q: lim d. (XS tan (5x)

A: Solution of limit is given below..

Q: 2x tan x+ cos I COS T lim

A:

Q: sin? (V6x) – x sin(6x) lim x→0 x4

A:

Q: 2) lim sin 4x

A:

Q: -2x – 1 Find lim X+0 sin 3 sin()

A: Using formulae of limits

Q: 44. lim sin² x 7/4

A: The limit is, 1/2 The detailed solution is as follows below :

Q: -2x 01. lim,-»o 4 sinx

A:

Q: 4 lim sin(x) х>0 х 41

A: Given that

Q: 5 sin(6x) lim x→0 3x

A:

Q: х(4+sin 6x) 3. lim X→+0 х+1

A:

Q: lim COS X tanx メー→o <-2メ4リX-8 2lim 3 メ→ 2 xリ_2X メ-2 xツ_2Xメ

A:

Q: Find the limit.

A: Our Aim is to evaluate limx→∞ x sin 1x -(i)

Q: Lim 8X +4=4 Cos X +tam

A: To find the given limit

Q: 3x+1 lim 1 sin x)

A: Given,         limx→03x+1x-1sinx

Q: 3. lim (x – 1) sin ,= 0

A:

Q: 10 sin(4x³) 12x8 lim X→0

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Evaluate

A: Our Aim is to evaluate the limit given below:-limx→0tan (2x)x-(i)