sing the following information:   Coefficients Intercept -12.8094 Independent variable 2.1794   ANOVA           df SS MS F Regression 1 12323.56 12323.56 90.0481 Residual 8 1094.842 136.8550   Total 9 13418.4       a) What is the standard error of the estimate? A) 136.8552 B) 1094.842 C) 11.6985 D) 13418.4 b) What is the coefficient of determination? Round the percentage to one decimal point. A) 91.8% B) 8.2% C) 90.0% D) 136.9% c) What is the correlation coefficient? A) 0.9184 B) 0.9583 C) −0.9583 D) 0.9004

A multiple regression analysis produced the following tables. Predictor Coefficients StandardErrort Statistic p-valueIntercept -139.609 2548.989 -0.05477 0.957154x 24.24619 22.25267 1.089586 0.295682x 32.10171 17.44559 1.840105 0.08869Source df SS MS F p-valueRegression 2 302689 151344.5 1.705942 0.219838Residual 13 1153309 88716.07Total 15 1455998Using = 0.01 to test the null hypothesis H :?1 = ?2 = 0, the critical F value is ____.6.701.964.845.995.70

a) which for these data is 32.1470, 42.3520, or 10.0674 c) that minimizes the error sum of squares, total sum of squares, or regression sum of squares…for which these data is 32.1470, 42.3520, or 10.0674

The following table was generated from the sample data of 10 college students regarding the number of parking tickets the student receives in a semester, the student's age, and the student's GPA. The dependent variable is the student's GPA, the first independent variable (x1) is the number of parking tickets, and the second independent variable (x2) is the student's age. Coefficients Standard Error p-value t-Stat Intercept 9.846834 1.636494 6.017030 0.000533 Number of Parking Tickets -0.190967 0.037496 -5.093039 0.001410 Student's Age -0.324988 0.084657 - 3.838877 0.006384 Copy Data Step 1 of 2: Write the multiple regression equation for the computer output given. Round your answers to three decimal places. 田 Tables E Keypad Answer How to enter your answer (opens in new window) Keyboard Shortcuts X +

Use the Stata output below to answer the following question. The data used in this analysis is from a sample of airlines. The variables used are: fare-avg price of a one-way fare, in dollars dist- distance of the flight, in miles .reg fare ldist. Source Model Residual 551.391705 Total lfare SS ldist _cons 875.094374 df The OLS results suggest that 1 323.702668 120024315 4,594 MS Coef. Std. Err. 4,595 190444913 Number of obs F(1, 4594) Prob > F R-squared Adj R-squared Root MSE t P>|t| .4025646 .0077517 51.93 0.000 2.399834 .0521601 46.01 0.000 4,596 2696.98 0.0000 0.3699 0.3698 .34645 [95% Conf. Intervall .3873676 .4177617 2.297575 2.502093 a 1% increase in distance is associated with approximately a $.40 increase in the price of the fare. a 1% increase in distance is associated with approximately a .40% increase in the price of the fare. a 1% increase in distance is associated with approximately a 40 % increase in the price of the fare. None of the above.

A sample of size 8 was collected from an unknown population 0 1126 10 11 20 1. Use the table of expected z-scores (rounded to the nearest tenth) below to construct the normality plot with expected z-scores on the x-axis and the observations on the y-axis: 5 -1.2 -0.5 0 0.5 1.2 Clear All Draw: 22- 2 not normal normal 19 # 6 -1.3 -0.6 -0.2 0.2 0.6 1.3 7 -1.4 -0.8 -0.4 0 0.4 0.8 1.4 8 -1.4 -0.9 -0.5 -0.2 0.2 0.5 0.9 1.4 9 -1.5 -0.9 -0.6 -0.3 0 0.3 0.6 0.9 1.5 2. Based on whether the pattern above is linear or not, in your opinion, was the sample drawn from a normal population or not?

Assume the variance for the following returns is 2597. What is X? Returns: -2X,-X,0,X,2X,3X (round your final answer to 1 decimal place: 20.456 -->20.4)   Answer:

Consider the following table: SS DF MS ? 10 10 7 706.87 15 Among Treatments 4468.45 Error Total Step 3 of 8: Calculate the mean square among treatments. Please round your answer to two decimal places. LL F