sinh-1 x dx.

Q: «) sin3x sinlx dY

A: See the details solution in below

Q: sin x - x dx = ?

A: Evaluate it.   ∫02sin x-xxdx

Q: solve dy/dx

A: Given: y=log57x3x+2ln(5)To find : dydx=?Formula: (logax)'=1x ln a

Q: STox -x* dx 2.

A: To Evaluate: ∫6x-x2dx

Q: 8 sint csc x dx

A:

Q: evaluate the integral.

A:

Q: (d) Find sinh¬1 x dx.

A: Find ∫01sinh-1x dx

Q: Í sinh(1 - 4x) dx Answer:

A: In this question we have to find the Integration.

Q: sinx dx √2-cos²x S

A:

Q: Je-2x sin 2x dx

A:

Q: sin(3x)e°*dx

A:

Q: dx 2. 2 - sinx

A:

Q: y=sinh (ln x).

A:

Q: sinh6x cosh2x cosh²x + sinh2:

A: Given,     ∫sinh6x cosh2xcosh2x+sinh2xdx=

Q: se*cosx dx e-sinx

A: Let sinx = u then cosxdx = du

Q: dy -y3tanx dx Solve sin2x

A: The given differential equation is: sin(2x) dydx-y=tan(x)

Q: dx sinhx

A:

Q: sinh v4x -dx: V4x

A: Here we use  ∫sinhx=coshx U-subsitution to evaluate the integral

Q: 4- у ду dx 2 ху +x = 0

A:

Q: cosh(2x + 9)dx

A: on doing integration with respect to x we will get

Q: 3x -1 dx is equal to

A:

Q: sech - x dx , 0 < x < 1

A:

Q: 4- x²+4 dx ht. 23

A: To evaluate∫x3x2+4dx We can find the integral by substitution method.

Q: [sinh(x)(x² + 7*)] dx a.

A: As per our guidelines we are supposed to answer only one question i.e. the first question. For the…

Q: dx sinh3x tanh3x S

A:

Q: sinh e Incot3x h- dx St 1+9x²

A:

Q: -1 2 sinx dx

A:

Q: 2 sec* dx

A:

Q: Evaluate sinh (9x)dx. | sinh (9x)dx =

A: We have to find the integral

Q: -1 Cosh-1 5x sinh 4x.

A:

Q: -dx 1 – sin(0)

A: To evaluate the integral.

Q: x² sinh x dx

A: Let's find.

Q: 5. Ò sin(x- )dx

A:

Q: tan 2x dx 2. S (3+ln cos 2x)6

A:

Q: cosh?x-sinh²x = 1 %3D

A:

Q: 4-S e²*sinx dx

A: We have to find the integration of the given function.

Q: | sin x (3cos*)dx 2:

A:

Q: -22 (sinhx+coshx) dx

A:

Q: 4x² sinh (x³) tanh (x³) dx

A:

Q: | cos x dx ile ( Jcos x| dx

A:

Q: 1- y '(2x) = Sinh

A: the question is taken from calculus and in which we have to find the derivative of the given…

Q: Se-Ax .sinh(2x) dx

A: We know, sinh(x)=ex-e-x2

Q: ' 7 cosh (x) dx = 1

A: We have to evaluate the integral ∫197coshxxdx

Q: + Sin (2x) de

A:

Q: 36" dx V6* +3 1.

A:

Q: tan-x dx

A:

Q: + 2sin(x) + 7e"dx

A:

Q: 3. S sinh(5x - 1) dx

A: 3. ∫sinh (5x-1) dx Let I =∫sinh (5x-1) dx Substitute u = 5x-1 dudx = 5dx = 15du

Q: 3. dx 6X dx VT-x2 1-x² Et2

A:

Q: 2) dx 4. - |

A: We can use method of substitution in order to solve the problem problem.