sog a oue3 deauad s e un ao q suaau poue ongr) uau +9 upp ow npG+C Contentasadal aagdw ds rs po suau nosaorunda pe suruny eu so pasn eu aqi 4 ps uor VNO4 ir6padde auny VNG aedap prunung anp oN ds aurs a u padnoul aq uePa ap para g od yNo sasshos a d por aayogrgoapal o a d ae spod dpon uaps uogexgp ao aueda doa f uep ao ao pasnq aq pos ogsp np as o oos aos rp anbsVN amp sposp a paoedau adn a adiii tan aS jo suaqua ssopaao aadap ap soU oipuqjo uawi o VNa snodogouoy os aed-asn) rPhenotypic Methodst ng po pea os azpaqy VNG jo spunas alothe complementary strands of DNA from one organism willS11 aandy) samnap VNa a seaoda aounqoqe LL p e VNG onos e qAn osge p Sun 4 pousaap aq u sVNa popas-anop pr aunaad poog uadeply on o 4 pdo p a und 1-V seaaspaosadoplg an 4 alo p a und an 0DNA Hybridizationdoo aaou ua uoq ospoo p ae s300bas ous esqou ao sY14101 ndy a0s) sds yaap jo sparsnoi uadj sp-dud paosoqu p 91 jo saanbos pse ouursoLndwoo so posng st dp a uy Aea os aopopondsa ead 1 paunduso3 aq ues spnpoad auad aac o16 01 aundy ao) s ad rosoqu paaaP jour se rao pea oppe u VNC OSs oposn sanbeupo paepors a papoap ou susjurao 1ur ieoaddeo aespe uy ssuporao eqeses d prsosoqu snouRA JOsa0p p VNG paps-aop ap p adp lq panseu ugo 00LAad up pynoo sas aouad poe saouebos apopa a s ao a mp e uessasaop ao vosodaoo ang po foursV poaeM aes ng bu N Si0en3.003.06e the widespread availability of wbole and partial penoeejoo s uoorngu YNG E 2ag u sa asal n pa sos anesog s sg 3aads pagarpsop undp o aaun uajo s y eupoa ssasts sg aubos VNG 0Ss lsogryo o saonbos yNQ Oss Sunureos sasnppamd aq wag u sanbos au pasuehas pur poopadepap Ngnss ap pue pr pps sads pr aa woy poe aq es yNd au 092 1e 0xuequosqe agejaVTSelectiha anprcedure hh faster most diructlyffee free atimiabyTypeaun berpopulationmples such ased using PCRbe comparedSTces of knownmas been verytantly relatedishing closelyed but geneti-al SSU rDNAs a better toolOs.0600artial genomeNN Dd d o-agnop se sase0 u 09denatures (melts)d amino acids for determin-a op auanbos YNa jo sohat it accountshniques usedanism has anrelated. A similarity of base compositions, however, does notfigure 10.9),atly expandedcomparisonsbosomal pro-igure 10.1b).termined, thenecessarily mean that the organisms are related, because thenucleotide sequences and genome sizes could differ greatly.The GC content is often measured by determining the tem-perature at which the double-stranded DNA denatures, or melts.DNA that has a high GC content melts at a higher temperaturebecause G-C base pairs are held together by three hydrogenbonds, whereas A-T pairs are held together by only two hydro-gen bonds. The temperature at which double-stranded DNAmelts can be determined by measuring the absorbance of UVlight by a solution of DNA as it is heated. The absorbance rap-idly increases as the DNA denatures (figure 10.15). ueUMI UEO

Question
Asked Oct 15, 2019
33 views

15. G + C Content: Describe how the G+C content of an organism can be measured. In your response, be sure to address the following:

b. Explain the principles behind a melting curve and how this helps determine G + C content. Include an explanation of the components of the curve and how one would interpret a melting curve.

sog a oue3 deauad s e un ao q sua
au poue ongr) uau +9 upp o
w np
G+C Content
asadal aag
dw ds rs po sua
u nosaorunda pe suruny eu s
o pasn eu aqi 4 ps uor VNO
4 ir6padde auny VNG aedap pr
unung anp oN ds aurs a u padnoul aq ue
Pa ap para g od yN
o sasshos a d por aay
ogrgo
apal o a d ae spo
d dpon uaps uogexgp ao aued
a doa f uep ao ao pasnq aq pos ogs
p np as o oos aos rp anbs
VN amp sposp a paoedau adn a ad
iii tan aS jo suaqua ssop
aa
o aadap ap soU oipuqjo ua
wi o VNa snodogouoy os aed-asn) r
Phenotypic Methods
t ng po pea os azpaqy VNG jo spunas alo
the complementary strands of DNA from one organism will
S11 aandy) samnap VNa a seao
da aounqoqe LL p e VNG onos e q
An osge p Sun 4 pousaap aq u s
VNa popas-anop pr aunaad poog uad
eply on o 4 pdo p a und 1-V seaaspao
sadoplg an 4 alo p a und an 0
DNA Hybridization
doo aaou ua uoq os
poo p ae s300bas ous esqou ao sY
14101 ndy a0s) sds yaap jo sparsnoi uadj sp
-dud paosoqu p 91 jo saanbos pse ouur
soLndwoo so posng st dp a uy Aea os ao
popondsa ead 1 paunduso3 aq ues spnpoad auad aac o
16 01 aundy ao) s ad rosoqu paaaP jo
ur se rao pea oppe u VNC OSs o
posn sanbeupo paepors a papoap ou susjurao 1u
r ieoaddeo aespe uy ssupora
o eqeses d prsosoqu snouRA JOsa0
p p VNG paps-aop ap p ad
p lq panseu ugo 00L
Aad up pynoo sas aouad poe saouebos apo
pa a s ao a mp e uessa
saop ao vosodaoo ang po foursV poa
e
M aes ng bu N Si0en
3.00
3.06
e the widespread availability of wbole and partial penoee
joo s uoorngu YNG E 2ag u sa a
sal n pa sos anesog s sg 3aads pagar
psop undp o aaun uajo s y e
upoa ssast
s sg aubos VNG 0Ss lsogry
o o saonbos yNQ Oss Sunureos sasnp
pamd aq wag u sanbos au pasuehas pur poop
ade
pap Ngnss ap pue pr p
ps sads pr aa woy poe aq es yNd
help_outline

Image Transcriptionclose

sog a oue3 deauad s e un ao q sua au poue ongr) uau +9 upp o w np G+C Content asadal aag dw ds rs po sua u nosaorunda pe suruny eu s o pasn eu aqi 4 ps uor VNO 4 ir6padde auny VNG aedap pr unung anp oN ds aurs a u padnoul aq ue Pa ap para g od yN o sasshos a d por aay ogrgo apal o a d ae spo d dpon uaps uogexgp ao aued a doa f uep ao ao pasnq aq pos ogs p np as o oos aos rp anbs VN amp sposp a paoedau adn a ad iii tan aS jo suaqua ssop aa o aadap ap soU oipuqjo ua wi o VNa snodogouoy os aed-asn) r Phenotypic Methods t ng po pea os azpaqy VNG jo spunas alo the complementary strands of DNA from one organism will S11 aandy) samnap VNa a seao da aounqoqe LL p e VNG onos e q An osge p Sun 4 pousaap aq u s VNa popas-anop pr aunaad poog uad eply on o 4 pdo p a und 1-V seaaspao sadoplg an 4 alo p a und an 0 DNA Hybridization doo aaou ua uoq os poo p ae s300bas ous esqou ao sY 14101 ndy a0s) sds yaap jo sparsnoi uadj sp -dud paosoqu p 91 jo saanbos pse ouur soLndwoo so posng st dp a uy Aea os ao popondsa ead 1 paunduso3 aq ues spnpoad auad aac o 16 01 aundy ao) s ad rosoqu paaaP jo ur se rao pea oppe u VNC OSs o posn sanbeupo paepors a papoap ou susjurao 1u r ieoaddeo aespe uy ssupora o eqeses d prsosoqu snouRA JOsa0 p p VNG paps-aop ap p ad p lq panseu ugo 00L Aad up pynoo sas aouad poe saouebos apo pa a s ao a mp e uessa saop ao vosodaoo ang po foursV poa e M aes ng bu N Si0en 3.00 3.06 e the widespread availability of wbole and partial penoee joo s uoorngu YNG E 2ag u sa a sal n pa sos anesog s sg 3aads pagar psop undp o aaun uajo s y e upoa ssast s sg aubos VNG 0Ss lsogry o o saonbos yNQ Oss Sunureos sasnp pamd aq wag u sanbos au pasuehas pur poop ade pap Ngnss ap pue pr p ps sads pr aa woy poe aq es yNd

fullscreen
au 092 1e 0xuequosqe ageja
VT
Selectiha an
prcedure hh faster most diructly
ffee free atimiaby
Type
aun ber
population
mples such as
ed using PCR
be compared
ST
ces of known
mas been very
tantly related
ishing closely
ed but geneti-
al SSU rDNA
s a better tool
Os
.06
00
artial genome
NN Dd d o-agnop se sase0 u 09
denatures (melts)
d amino acid
s for determin-
a op auanbos YNa jo so
hat it accounts
hniques used
anism has an
related. A similarity of base compositions, however, does not
figure 10.9),
atly expanded
comparisons
bosomal pro-
igure 10.1b).
termined, the
necessarily mean that the organisms are related, because the
nucleotide sequences and genome sizes could differ greatly.
The GC content is often measured by determining the tem-
perature at which the double-stranded DNA denatures, or melts.
DNA that has a high GC content melts at a higher temperature
because G-C base pairs are held together by three hydrogen
bonds, whereas A-T pairs are held together by only two hydro-
gen bonds. The temperature at which double-stranded DNA
melts can be determined by measuring the absorbance of UV
light by a solution of DNA as it is heated. The absorbance rap-
idly increases as the DNA denatures (figure 10.15). ue
UMI UEO
help_outline

Image Transcriptionclose

au 092 1e 0xuequosqe ageja VT Selectiha an prcedure hh faster most diructly ffee free atimiaby Type aun ber population mples such as ed using PCR be compared ST ces of known mas been very tantly related ishing closely ed but geneti- al SSU rDNA s a better tool Os .06 00 artial genome NN Dd d o-agnop se sase0 u 09 denatures (melts) d amino acid s for determin- a op auanbos YNa jo so hat it accounts hniques used anism has an related. A similarity of base compositions, however, does not figure 10.9), atly expanded comparisons bosomal pro- igure 10.1b). termined, the necessarily mean that the organisms are related, because the nucleotide sequences and genome sizes could differ greatly. The GC content is often measured by determining the tem- perature at which the double-stranded DNA denatures, or melts. DNA that has a high GC content melts at a higher temperature because G-C base pairs are held together by three hydrogen bonds, whereas A-T pairs are held together by only two hydro- gen bonds. The temperature at which double-stranded DNA melts can be determined by measuring the absorbance of UV light by a solution of DNA as it is heated. The absorbance rap- idly increases as the DNA denatures (figure 10.15). ue UMI UEO

fullscreen
check_circle

Expert Answer

Step 1

DNA is made of several nucleotides. Each nucleotide consists of a sugar molecule, a phosphate group, and a nitrogenous base. Four types of nitrogenous bases are found in DNA, adenine, guanine, cytosine, and thymidine. The sequence of bases in the DNA determines the genetic code.

Step 2

DNA base pairs are complementary to each other. Adenine pairs with thymine using two hydrogen bonds and guanine pairs with cytosine using 3 hydrogen bonds. The GC content measures the amount (in percentage) of nitrogenous base cytosine and guanine in DNA or RNA.Several methods are used in the determination of GC content of DNA molecules like flow cytometry or sequencing that can be done. The most common technique used in the calculation of GC content is by measuring the melting temperature of the DNA fragment under observation. 

 

Step 3

The melting temperature (Tm) is defined as the temperature at which half the amount of double-stranded DNA is converted to a single-stranded form. High melting temperature means high GC content is present in the DNA because these are held together by three hydrogen bonds. AT are bonded together by two hydrogen bonds; three hydrogen bonds require a high amoun...

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Biology

Related Biology Q&A

Find answers to questions asked by student like you

Show more Q&A add
question_answer

Q: Can you please check my answer and make sure it is correct? Question: Why are hydrogen bonds so vita...

A: Hydrogen bonds are a type of attractive interaction between an electronegative atom and a hydrogen a...

question_answer

Q: What is the benefit of Photorespiration in plants and what problem does it pose in many plants?

A: The photorespiration is the process of plant metabolism in which the enzyme Ribulose- 1, 5-bisphosph...

question_answer

Q: Choose which substances cannot pass through the phospholipid bilayer of the plasma membrane.  A. Gas...

A: Phospholipids:These are a type of lipids. A phospholipid molecule structure usually contains two hyd...

question_answer

Q: What advantages do flowers give angiosperms over gymnosperms?

A: Angiosperm are flowering plants which is largest and most diverse group of kingdom plantae. Angiospe...

question_answer

Q: Two genes, A and X, exhibit incomplete linkage. The frequency of the parental gametes (AX and ax) is...

A: When genes exhibiting different traits are located on the same chromosomes they are said to be linke...

question_answer

Q: Place the labels in order, denoting the sequence of events of the cardiac cycle beginning with resti...

A: Cardiac cycle is the performance of the human heart from the ending of one heartbeat to the beginnin...

question_answer

Q: In mice, there is an allele that in the heterozygous condition, produces mice with yellow coats. Mic...

A: The male yellow mouse and female yellow mice that have mated to produce offspring must be heterozygo...

question_answer

Q: What are representatives of Hepaticophyta, Bryophyta, Anthocerophyta?  What are representatives of P...

A: Bryophytes are the group consisting of three types of non-vascular plants.The representatives of thi...

question_answer

Q: O2-binding curves 1 0.9 0.8 2 0.7 3 0.6 0.5 0.4 0.3 0.2 0.1 100 120 20 40 60 80 po2 (torr) Fractiona...

A: The oxygen–haemoglobin dissociation curve is used to plot the amount of haemoglobin in its saturated...