Solution 1.43 dy (a) Let be the gradient at a fixed point (x, y) on the curve, with x ≥ 0 and y ≥ 0. Then the equation of the tangent line at this point is da dy Y-y=(X-x), da where X and Y vary along the line. When X = 0, we have Y=y- dz' and the given condition then becomes dy dx 2 dy da +1=y-x- How Come??

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