Solve for all degree solutions and 0 if 0° < 0 < 360°. Do not use a calculator. (Enter your answers as a comma-separated list.) V2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0 = 0° + 180°k, 225° + 360°k, 315° + 360°k 0 = 0° + 180°k, 45° + 360°k, 45° + 180°k 0 = 360°k, 225° + 360°k, 315° + 360°k O e = 360°k, 45° + 360°k, 45° + 180°k 0 = 180° + 360°k, 225° + 360°k, 315° + 360°k (b) O if 0° < 0 < 360°

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section: Chapter Questions
Problem 35RE
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Solve for all degree solutions and 0 if 0° < 0 < 360°. Do not use a calculator. (Enter your answers as a comma-separated list.)
V2 tan 0 + 2 sin 0 tan 0
= 0
(a) all degree solutions (Let k be any integer.)
0° + 180°k, 225° + 360°k, 315° + 360°k
= A
0° + 180°k, 45° + 360°k, 45° + 180°k
360°k, 225° + 360°k, 315° + 360°k
360°k, 45° + 360°k, 45° + 180°k
180° + 360°k, 225° + 360°k, 315° + 360°k
%D
(b) 0 if 0° <0 < 360°
Transcribed Image Text:Solve for all degree solutions and 0 if 0° < 0 < 360°. Do not use a calculator. (Enter your answers as a comma-separated list.) V2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0° + 180°k, 225° + 360°k, 315° + 360°k = A 0° + 180°k, 45° + 360°k, 45° + 180°k 360°k, 225° + 360°k, 315° + 360°k 360°k, 45° + 360°k, 45° + 180°k 180° + 360°k, 225° + 360°k, 315° + 360°k %D (b) 0 if 0° <0 < 360°
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