Question

Asked Jan 26, 2020

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Solve the equation for all solutions in the interval [0,2π).

sin(3x)=−√3/2

Express each solution in radians in exact form. Enter the solutions as a comma‑separated list.

Step 1

Find 3x using sin inverse.

Step 2

Sin is negative in 3rd and fourth quadrant.

sin^-1(-sqrt(3)/2)= 4pi/3 and 5pi/3 in [0,2pi].

We add 2n*pi with the solutions to find the general solutions.

Step 3

Find x by dividing ...

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