Solve the problem. The quality of the images from an orbital telescope result from a large parabolic mirror, 3.8 meters in diameter, that collects light from space. Suppose that a coordinate system is chosen so that the vertex of a cross section through the center of the mirror is located at (0, 0). Furthermore, the focal length of the mirror is 56.8m. Assume that x and y are in meters. Write an equation of the parabolic cross section of the mirror for -1.9 ≤ x ≤ 1.9. Select one: O a. x² = = 227.2y for -1.9 ≤ x ≤ 1.9 O b. x² = 113.6y for -1.9 ≤ x ≤ 1.9 O c. x² = 56.8y for -1.9 ≤ x ≤ 1.9 O d. y² = 227,2x for -1.9 ≤ y ≤ 1,9

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.2: Ellipses
Problem 32E
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Solve the problem.
The quality of the images from an orbital telescope result from a large parabolic mirror, 3.8 meters in diameter, that collects light from space.
Suppose that a coordinate system is chosen so that the vertex of a cross section through the center of the mirror is located at (0, 0). Furthermore,
the focal length of the mirror is 56.8m. Assume that x and y are in meters. Write an equation of the parabolic cross section of the mirror for
-1.9 ≤ x ≤ 1.9.
Select one:
O a. x² = 227.2y for -1.9 ≤ x ≤ 1.9
O b. x²
113.6y for -1.9 ≤ x ≤ 1.9
O c. x² = 56.8y for -1.9 ≤ x ≤ 1.9
O d. y² = 227.2x for -1.9 ≤ y ≤ 1.9
=
Transcribed Image Text:Solve the problem. The quality of the images from an orbital telescope result from a large parabolic mirror, 3.8 meters in diameter, that collects light from space. Suppose that a coordinate system is chosen so that the vertex of a cross section through the center of the mirror is located at (0, 0). Furthermore, the focal length of the mirror is 56.8m. Assume that x and y are in meters. Write an equation of the parabolic cross section of the mirror for -1.9 ≤ x ≤ 1.9. Select one: O a. x² = 227.2y for -1.9 ≤ x ≤ 1.9 O b. x² 113.6y for -1.9 ≤ x ≤ 1.9 O c. x² = 56.8y for -1.9 ≤ x ≤ 1.9 O d. y² = 227.2x for -1.9 ≤ y ≤ 1.9 =
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