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Solve the system by substitution: {x-7y=(-46) <1st equation>; 2x-6y=(-44)<2nd equation> I have tried reducing the 2nd equation to have it equal to x to plug into 1st equation, which gave me 3y-22-7y=(-46) after plugging. What I got for y was (-6), I then plugged (-6) into 2nd equation in original form and got (-40) for x. My answer of (-40,-6) was

Solve the system by substitution: {x-7y=(-46) <1st equation>; 2x-6y=(-44)<2nd equation> I have tried reducing the 2nd equation to have it equal to x to plug into 1st equation, which gave me 3y-22-7y=(-46) after plugging. What I got for y was (-6), I then plugged (-6) into 2nd equation in original form and got (-40) for x. My answer of (-40,-6) was

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter12: Algebra Of Matrices
Section12.CT: Test
Problem 20CT
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Solve the system by substitution: {x-7y=(-46) <1st equation>; 2x-6y=(-44)<2nd equation>

I have tried reducing the 2nd equation to have it equal to x to plug into 1st equation, which gave me 3y-22-7y=(-46) after plugging. What I got for y was (-6), I then plugged (-6) into 2nd equation in original form and got (-40) for x. My answer of (-40,-6) was incorrect, please tell me what I have done wrong. 

 

2 Solve the system 2x-by=-44 SX-7 y = - 46 22x-6y=-44 +y + by 3y₁-22= 74= -46 - 4x = 24 by substitution: hh-19=xx 9h²=82-1₂- Z + 8 + h2=17₁₂- 2 2 2 =22-K₂=X hh-=(9-)9-X2< ht==9+X7 -92-98- t₁- ti 08-=XX (OH- )= X < = [(9-) = k 2 x (9-Oh-
Transcribed Image Text:2 Solve the system 2x-by=-44 SX-7 y = - 46 22x-6y=-44 +y + by 3y₁-22= 74= -46 - 4x = 24 by substitution: hh-19=xx 9h²=82-1₂- Z + 8 + h2=17₁₂- 2 2 2 =22-K₂=X hh-=(9-)9-X2< ht==9+X7 -92-98- t₁- ti 08-=XX (OH- )= X < = [(9-) = k 2 x (9-Oh-
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