Question
Asked Dec 11, 2019
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Solve the system.

x+4y+3z=-6

3y+2z=-8

z=2

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Expert Answer

Step 1

Step 2

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3y + 2(2) =-8 3y + 4 =-8 3y =-12 y = -4

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Step 3

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x+ 4(-4)+3(2)=-6 x- 16 + 6=-6 x– 10 = -6

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